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Use the Standard Reaction Enthalpies Given Below to Determine

Question 78

Multiple Choice

Use the standard reaction enthalpies given below to determine Use the standard reaction enthalpies given below to determine H° for the following reaction: P<sub>4</sub>(g) + 10Cl<sub>2</sub>(g) → 4PCl<sub>5</sub>(s) H°<sub> </sub>= ? Given: PCl<sub>5</sub>(s) → PCl<sub>3</sub>(g) + Cl<sub>2</sub>(g) H°= +157 kJ P<sub>4</sub>(g) + 6Cl<sub>2</sub>(g) → 4PCl<sub>3</sub>(g) H° = -1207 kJ A) -1835 kJ mol<sup>-1</sup> B) -1364 kJ mol<sup>-1</sup> C) -1050 kJ mol<sup>-1</sup> D) -1786 kJ mol<sup>-1</sup> E) -2100 kJ mol<sup>-1</sup> H° for the following reaction: P4(g) + 10Cl2(g) → 4PCl5(s) Use the standard reaction enthalpies given below to determine H° for the following reaction: P<sub>4</sub>(g) + 10Cl<sub>2</sub>(g) → 4PCl<sub>5</sub>(s) H°<sub> </sub>= ? Given: PCl<sub>5</sub>(s) → PCl<sub>3</sub>(g) + Cl<sub>2</sub>(g) H°= +157 kJ P<sub>4</sub>(g) + 6Cl<sub>2</sub>(g) → 4PCl<sub>3</sub>(g) H° = -1207 kJ A) -1835 kJ mol<sup>-1</sup> B) -1364 kJ mol<sup>-1</sup> C) -1050 kJ mol<sup>-1</sup> D) -1786 kJ mol<sup>-1</sup> E) -2100 kJ mol<sup>-1</sup> H° = ?
Given:
PCl5(s) → PCl3(g) + Cl2(g) Use the standard reaction enthalpies given below to determine H° for the following reaction: P<sub>4</sub>(g) + 10Cl<sub>2</sub>(g) → 4PCl<sub>5</sub>(s) H°<sub> </sub>= ? Given: PCl<sub>5</sub>(s) → PCl<sub>3</sub>(g) + Cl<sub>2</sub>(g) H°= +157 kJ P<sub>4</sub>(g) + 6Cl<sub>2</sub>(g) → 4PCl<sub>3</sub>(g) H° = -1207 kJ A) -1835 kJ mol<sup>-1</sup> B) -1364 kJ mol<sup>-1</sup> C) -1050 kJ mol<sup>-1</sup> D) -1786 kJ mol<sup>-1</sup> E) -2100 kJ mol<sup>-1</sup> H°= +157 kJ
P4(g) + 6Cl2(g) → 4PCl3(g) Use the standard reaction enthalpies given below to determine H° for the following reaction: P<sub>4</sub>(g) + 10Cl<sub>2</sub>(g) → 4PCl<sub>5</sub>(s) H°<sub> </sub>= ? Given: PCl<sub>5</sub>(s) → PCl<sub>3</sub>(g) + Cl<sub>2</sub>(g) H°= +157 kJ P<sub>4</sub>(g) + 6Cl<sub>2</sub>(g) → 4PCl<sub>3</sub>(g) H° = -1207 kJ A) -1835 kJ mol<sup>-1</sup> B) -1364 kJ mol<sup>-1</sup> C) -1050 kJ mol<sup>-1</sup> D) -1786 kJ mol<sup>-1</sup> E) -2100 kJ mol<sup>-1</sup> H° = -1207 kJ


A) -1835 kJ mol-1
B) -1364 kJ mol-1
C) -1050 kJ mol-1
D) -1786 kJ mol-1
E) -2100 kJ mol-1

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