Exam 1: Topics From Algebra

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Solve the inequality. x−2x2−5x−14≥0\frac { x - 2 } { x ^ { 2 } - 5 x - 14 } \geq 0

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D

The braking distance d (in feet) of a certain car traveling v mi/hr is given by the equation d=v+(v2/40)d = v + \left( v ^ { 2 } / 40 \right) Determine the velocities that result in braking distances of less than 30 feet.

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B

Express as a sum of terms of the form axγa x ^ { \gamma } , where r is a rational number. (x2+6)2x5\frac { \left( x ^ { 2 } + 6 \right) ^ { 2 } } { x ^ { 5 } }

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C

Express the interval (2, 11) as an inequality in the variable x.

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The two given numbers are coordinates of points AA and B\mathcal { B } , respectively, on a coordinate line. Express the indicated statement as an inequality involving the absolute value symbol. χ\chi , −3;d(A,B)- 3 ; d ( A , B ) is at least 66

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Express as a quotient. x−1/5−x9/5x ^ { - 1 / 5 } - x ^ { 9 / 5 }

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Solve the inequality. ∣2x+13∣≤−13| 2 x + 13 | \leq - 13

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Solve the inequality. −2<∣x∣<9- 2 < | x | < 9

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Simplify the expression. 3a2+20a+25a4−625÷9a2+30a+25a2−5a\frac { 3 a ^ { 2 } + 20 a + 25 } { a ^ { 4 } - 625 } \div \frac { 9 a ^ { 2 } + 30 a + 25 } { a ^ { 2 } - 5 a }

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Simplify the expression. (−243x5y−10)25\left( \frac { - 243 x ^ { 5 } } { y ^ { - 10 } } \right) ^ { \frac { 2 } { 5 } }

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A large grain silo is to be constructed in the shape of a circular cylinder with a hemisphere attached to the top (see the figure). The diameter of the silo is to be 36 feet, but the height is yet to be determined. Find the height h of the silo that will result in a capacity of 15,876 π ft 3 . A large grain silo is to be constructed in the shape of a circular cylinder with a hemisphere attached to the top (see the figure). The diameter of the silo is to be 36 feet, but the height is yet to be determined. Find the height h of the silo that will result in a capacity of 15,876 π ft <sup> 3 </sup>.

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Solve the inequality. (x+2)(x−4)(11−x)≤0( x + 2 ) ( x - 4 ) ( 11 - x ) \leq 0

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Express the inequality −1≥x>−8- 1 \geq x > - 8 as an interval.

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Find the solutions of the equation. x3−343=0x ^ { 3 } - 343 = 0

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Rewrite the expression using a radical. 8−y188 - y ^ { \frac { 1 } { 8 } }

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Solve the inequality. 1x−3≥5x+6\frac { 1 } { x - 3 } \geq \frac { 5 } { x + 6 }

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Archeologists can determine the height of a human without having a complete skeleton. If an archeologist finds only a humerus, then the height of the individual can be determined by using a simple linear relationship. (The humerus is the bone between the shoulder and the elbow.) For a female, if x is the length of the humerus (in centimeters), then her height h (in centimeters) can be determined using the formula h=65+3.14xh = 65 + 3.14 x . For a male, h=73.6+3.0xh = 73.6 + 3.0 x should be used. A female skeleton having a 31-centimeter humerus is found. Find the woman's height at death.

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O'Carroll's formula is used to handicap weight lifters. If a lifter, who weighs bb kilograms, lifts ww kilograms of weight, then the handicapped weight W is given by: W=wb−353W = \frac { w } { \sqrt [ 3 ] { b - 35 } } Suppose two lifters weighing 73 kilograms and 89 kilograms lift weights of 273 kilograms and 210 kilograms, respectively. Use O'Carroll's formula to determine the superior weight lifter.

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Solve the equation. 5x−16=3(x−2)5 x - 16 = 3 ( x - 2 )

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Find the solutions of the equation. x3+3x2+5x=0x ^ { 3 } + 3 x ^ { 2 } + 5 x = 0

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