Exam 9: Analytical Trigonometry

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Use the given information to compute tan⁡(s+t)\tan ( s + t ) and tan⁡(s−t)\tan ( s - t ) . tan⁡s=5\tan s = 5 and tan⁡t=4\tan t = 4

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Evaluate the quantity without using a calculator or tables. sin⁡(tan⁡−1(−1))\sin \left( \tan ^ { - 1 } ( - 1 ) \right)

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Use the addition formulas for sine and cosine to simplify the expression. cos⁡(θ−π3)+cos⁡(θ+π3)\cos \left( \theta - \frac { \pi } { 3 } \right) + \cos \left( \theta + \frac { \pi } { 3 } \right)

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B

Use the addition formulas for tangent to simplify the expression. tan⁡2π7−tan⁡5π421+tan⁡2π7tan⁡5π42\frac { \tan \frac { 2 \pi } { 7 } - \tan \frac { 5 \pi } { 42 } } { 1 + \tan \frac { 2 \pi } { 7 } \tan \frac { 5 \pi } { 42 } }

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Evaluate the quantity without using a calculator or tables. tan⁡(arccos⁡1213)\tan \left( \arccos \frac { 12 } { 13 } \right)

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Use a product-to-sum formula to convert the expression to a sum or difference. Simplify where possible. cos⁡47∘cos⁡43∘\cos 47 ^ { \circ } \cos 43 ^ { \circ }

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Convert the expression into a product. Simplify where possible. cos⁡3π8−sin⁡π8\cos \frac { 3 \pi } { 8 } - \sin \frac { \pi } { 8 } (Hint: Use the identity cos⁡θ=sin⁡(π2−θ)\cos \theta = \sin \left( \frac { \pi } { 2 } - \theta \right) .)

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Compute cos⁡(α+θ)\cos ( \alpha + \theta ) and cos⁡(α−θ)\cos ( \alpha - \theta ) using the data below. sin⁡α=35 where π2<α<π\sin \alpha = \frac { 3 } { 5 } \quad \text { where } \frac { \pi } { 2 } < \alpha < \pi cos⁡θ=513 where −2π<θ<−3π2\cos \theta = \frac { 5 } { 13 } \quad \text { where } - 2 \pi < \theta < - \frac { 3 \pi } { 2 }

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Refer to the triangle and compute sin⁡2s\sin 2 s .  Refer to the triangle and compute  \sin 2 s  .

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Evaluate the given quantity, but do not use a calculator or table. cos⁡−1(−12)\cos ^ { - 1 } \left( - \frac { 1 } { 2 } \right)

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Evaluate the quantity without using a calculator or tables. cos⁡(arctan⁡13)\cos \left( \arctan \frac { 1 } { \sqrt { 3 } } \right)

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Use the given information to compute cos⁡(θ2)\cos \left( \frac { \theta } { 2 } \right) . sin⁡θ=−18\sin \theta = - \frac { 1 } { 8 } and 180∘<θ<270∘180 ^ { \circ } < \theta < 270 ^ { \circ }

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Compute sin⁡(α−β)\sin ( \alpha - \beta ) and cos⁡(α−β)\cos ( \alpha - \beta ) using the data below. sin⁡α=1213 where π2<α<π\sin \alpha = \frac { 12 } { 13 } \quad \text { where } \frac { \pi } { 2 } < \alpha < \pi cos⁡β=−1517 where π<β<3π2\cos \beta = - \frac { 15 } { 17 } \quad \text { where } \pi < \beta < \frac { 3 \pi } { 2 }

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Use the following information to evaluate the expression. cos⁡θ=1213(3π2<θ<2π)\cos \theta = \frac { 12 } { 13 } \quad \left( \frac { 3 \pi } { 2 } < \theta < 2 \pi \right) tan⁡(θ2)=?\tan \left( \frac { \theta } { 2 } \right) = ?

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Determine all of the solutions in the interval 0∘≤θ≤180∘0 ^ { \circ } \leq \theta \leq 180 ^ { \circ } . tan⁡2θ=−33\tan 2 \theta = - \frac { \sqrt { 3 } } { 3 }

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Find the right side of the identity. sin⁡s+sin⁡tsin⁡s+sin⁡t=?\frac { \sin s + \sin t } { \sin s + \sin t } = ?

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Use a product-to-sum formula to convert the expression to a sum or difference. Simplify where possible. cos⁡π5cos⁡4π5\cos \frac { \pi } { 5 } \cos \frac { 4 \pi } { 5 }

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Refer to the triangle and compute tan⁡(t2)\tan \left( \frac { t } { 2 } \right) .  Refer to the triangle and compute  \tan \left( \frac { t } { 2 } \right)  .

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Is t=π3t = \frac { \pi } { 3 } a solution of 2sin⁡t+2cos⁡t=3−12 \sin t + 2 \cos t = \sqrt { 3 } - 1 ?

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Use the given information to compute cos⁡(θ2)\cos \left( \frac { \theta } { 2 } \right) . cos⁡θ=47\cos \theta = \frac { 4 } { 7 } and 3π2<θ<2π\frac { 3 \pi } { 2 } < \theta < 2 \pi

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