Exam 5: Exponential and Logarithmic Functions

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If log 2 = 0.3010 and log 3 = 0.4771,then log If log 2 = 0.3010 and log 3 = 0.4771,then log   = =

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Solve the equation for x in terms of y: 1.2y = log Solve the equation for x in terms of y: 1.2y = log

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A certain medicine reduces the bacteria present by 25% each day.Currently 28,000 bacteria are present.Make a table of values for the number of bacteria present each day for 0 to 4 days.For each day write an expression for the number of bacteria as a product of 28,000 and a power of 0.75.Use the expressions to make an entry in your table for the number of bacteria after t days.write a function N for the number of bacteria after t days.

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Assume that log 3 = 0.4771 and log 4 = 0.6021.Determine the value of log 12.

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If If   - 5 = 3,then x = - 5 = 3,then x =

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Graph f(x)= Graph f(x)=    - 2  - 2 Graph f(x)=    - 2

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If a car is depreciating by 12.5% each year and the current amount is 0.5 its original value,then the situation can be represented by 0.5 = If a car is depreciating by 12.5% each year and the current amount is 0.5 its original value,then the situation can be represented by 0.5 =        .Represent this equation in logarithmic form. If a car is depreciating by 12.5% each year and the current amount is 0.5 its original value,then the situation can be represented by 0.5 =        .Represent this equation in logarithmic form. .Represent this equation in logarithmic form.

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Writing 2 ln x - Writing 2 ln x -   ln y + 4 ln z as a single logarithm gives ln y + 4 ln z as a single logarithm gives

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Solve for x: Solve for x:    3 =  3 = Solve for x:    3 =

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If If   x = -3,then x = x = -3,then x =

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If $1000 is invested for 2 years at 6% compounded quarterly,then the compound amount at the end of the period is

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Graph f(x)= 3 Graph f(x)= 3      Graph f(x)= 3

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Evaluate and simplify: Evaluate and simplify:

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Suppose an investment increases by 10% every year.Graph the number of years invested as a function of the multiplicative increase in original investment.Label the graph with the name of the function. Suppose an investment increases by 10% every year.Graph the number of years invested as a function of the multiplicative increase in original investment.Label the graph with the name of the function.

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The population in the state of California is 24 million today.It is increasing at a rate of 0.9% per year.The population t years from now is given by the rule P = 24 The population in the state of California is 24 million today.It is increasing at a rate of 0.9% per year.The population t years from now is given by the rule P = 24    .After how many years will the population double? .After how many years will the population double?

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Suppose an investment triples every decade.Graph the number of decades invested as a function of the multiplicative increase in original investment.Label the graph with the name of the function. Suppose an investment triples every decade.Graph the number of decades invested as a function of the multiplicative increase in original investment.Label the graph with the name of the function.

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Assume that log 5 = 0.6690.Determine the value of log Assume that log 5 = 0.6690.Determine the value of log    . .

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Graph f(x)= Graph f(x)=      Graph f(x)=

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Solve for x: ln(x + 1)- ln x = ln 2

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What power of 3 is 36?

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