Exam 20: Induced Voltages and Inductance: Part A

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A current-carrying wire of length 50 cm is positioned perpendicular to a uniform magnetic field.If the current is 10.0 A and it is determined that there is a resultant force of 7.5 N on the wire due to the interaction of the current and field,what is the magnetic field strength?

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A proton moving at a speed of 3.8 × 106 m/s cuts across the lines of a magnetic field at an angle of 40°.The strength of the field is 0.25 × 10−4 T.What is the magnitude of the force acting on the proton? (qp = 1.6 × 10−19 C)

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Two long parallel wires 40 cm apart are carrying currents of 10 A and 30 A in the opposite direction.What is the magnitude of the magnetic field halfway between the wires?

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The magnetic force on a charged particle moving at a constant speed in a uniform magnetic field will be halved when the angle between the velocity of the particle and the direction of the magnetic field changes from 25.0° to

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A solenoid with 500 turns,0.10 m long,carrying a current of 2.0 A and with a radius of 10−2 m will have what strength magnetic field at its center? (magnetic permeability in empty space µ0 = 4π × 10−7 T⋅m/A)

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An electron is moving at a speed of 12 × 106 m/s at an angle of 30° with respect to a uniform magnetic field of 8.0 × 10-4 T.What is the radius of the resulting helical path? (me = 9.11 × 10-31 kg,qe = 1.6 × 10-19 C)

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