Exam 6: Quadratic Equations and Inequalities

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Use the discriminant to determine what type of solutions exist for the quadratic equation. Do not solve the equation. 3z2−8z−3=03 z ^ { 2 } - 8 z - 3 = 0

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Simplify the expression. Enter the answer in a + bi form. (7+−15)(3−−17)( 7 + \sqrt { - 15 } ) ( 3 - \sqrt { - 17 } )

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Solve the inequality. x2−8x+12<0x ^ { 2 } - 8 x + 12 < 0

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Write −6−48- 6 \sqrt { - 48 } in terms of i and simplify.

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Write the expression in a+bia + b i form. 3+2i3−2i\frac { \sqrt { 3 } + \sqrt { 2 } i } { \sqrt { 3 } - \sqrt { 2 } i }

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Use the quadratic formula to find all real solutions of the equation. x2−11x+24=0x ^ { 2 } - 11 x + 24 = 0

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Simplify the expression. Enter the answer in a + bi form. (5+8i)+(1−3i)( 5 + 8 i ) + ( 1 - 3 i )

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