Exam 11: Quadratic Equations

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Solve the equation. x2−13x+42=0x ^ { 2 } - 13 x + 42 = 0

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Draw the graph of the equation and label the vertex. y=−x2+2x+12y = - x ^ { 2 } + 2 x + 12

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Solve the equation using the quadratic formula. Check your solution. y2+5y−24=0y ^ { 2 } + 5 y - 24 = 0

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Find the value of a, b, and c in the equation. 9z2+z−5=09 z ^ { 2 } + z - 5 = 0

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Solve the equation using the quadratic formula. Check your solution. x2−x−42=0x ^ { 2 } - x - 42 = 0

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Solve the equation. x2−13x=36x ^ { 2 } - 13 x = 36

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The perimeter of a rectangle is 200200 m, and its area is 2,400 m22,400 \mathrm {~m} ^ { 2 } . Find its dimensions.

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Solve the equation using the quadratic formula (when necessary, round results to three significant digits). 4x2+9x+3=04 x ^ { 2 } + 9 x + 3 = 0

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Solve the quadratic equation using the quadratic formula (if necessary, round the result to three significant digits). x2−x+3=0x ^ { 2 } - x + 3 = 0

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A rectangle is 3 ft longer than it is wide. The area of the rectangle is 54 ft 2. Use a quadratic equation to find the dimensions of the rectangle. A rectangle is 3 ft longer than it is wide. The area of the rectangle is 54 ft <sup>2</sup>. Use a quadratic equation to find the dimensions of the rectangle.

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Solve the equation. 77x2+170x+77=077 x ^ { 2 } + 170 x + 77 = 0

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Draw the graph of the equation and label the vertex. y=x2−2y = x ^ { 2 } - 2

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Solve the quadratic equation using the quadratic formula (if necessary, round the result to three significant digits). 2x 2 + 1 = x

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A 1,7001,700 -ft2 storage building 55 ft high is needed to store yard maintenance equipment. What dimensions should be used to minimize the outside walls?

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Solve the equation using the quadratic formula (when necessary, round results to three significant digits). y2=19y+7y ^ { 2 } = 19 y + 7

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A rectangular piece of sheet metal is 22 ft longer than it is wide. (See the figure below.) The area of the piece of sheet metal is 48ft248 \mathrm { ft } ^ { 2 } . Find its length and width.  A rectangular piece of sheet metal is  2  ft longer than it is wide. (See the figure below.) The area of the piece of sheet metal is  48 \mathrm { ft } ^ { 2 }  . Find its length and width.   lenght =                 ft width =                ft lenght =                 ft width =                ft

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Solve the equation. x2−x=42x ^ { 2 } - x = 42

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Draw the graph of the equation and label the vertex. y=−0.4x2+2.4x+0.7y = - 0.4 x ^ { 2 } + 2.4 x + 0.7

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Express the number in terms of j (if necessary, round the result to three significant digits). −529\sqrt { - 529 }

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Simplify. j14j ^ { 14 }

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