Exam 9: More on Inequalities

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Solve and graph. - x≤2 or x≥6x \leq 2 \text { or } x \geq 6  Solve and graph. - x \leq 2 \text { or } x \geq 6

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Write interval notation. - {x∣x≥}\{ x \mid x \geq \}

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Solve. - −4(2x+1)≥3[3x−2(x+1)]- 4 ( 2 x + 1 ) \geq 3 [ 3 x - 2 ( x + 1 ) ]

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Choose the number that is a solution of the inequality. - f−12<−4f - 12 < - 4

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Write interval notation for the graph. -Write interval notation for the graph. -

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Solve. - −6<x+9<5- 6 < x + 9 < 5

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Solve and graph. - −15<7x−1- 15 < 7 x - 1 and 5x−9<15 x - 9 < 1  Solve and graph. - - 15 < 7 x - 1  and  5 x - 9 < 1

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Solve and graph. Write the result in interval notation. - 9x<−549 x < - 54  Solve and graph. Write the result in interval notation. - 9 x < - 54

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Solve. - 0.2(4x−3)<1.2−(x+2)0.2 ( 4 x - 3 ) < 1.2 - ( x + 2 )

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Solve. - −23<19x−3≤23- \frac { 2 } { 3 } < \frac { 1 } { 9 } x - 3 \leq \frac { 2 } { 3 }

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Find the indicated intersection or union. - {q,s,u,v,w,x,y,z}∩{q,s,y,z}\{ q , s , u , v , w , x , y , z \} \cap \{ q , s , y , z \}

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Solve the compound inequality. Express the solution using interval notation. Graph the solution set. - x>5x > 5 or x<5x < 5  Solve the compound inequality. Express the solution using interval notation. Graph the solution set. - x > 5  or  x < 5

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Solve. -Jon has 1155 points in his math class. He must have 86%86 \% of the 1500 points possible by the end of the term to receive credit for the class. What is the minimum number of additional points he must earn by the end of the term to receive credit for the class?

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Write interval notation for the graph. -Write interval notation for the graph. -

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Find the indicated intersection or union. - {v,w,x,y,z}∪{q,s,y,z}\{ v , w , x , y , z \} \cup \{ q , s , y , z \}

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Solve and graph. Write the result in interval notation. - f−4<8f - 4 < 8  Solve and graph. Write the result in interval notation. - f - 4 < 8

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Solve. - 2≤73x−5<232 \leq \frac { 7 } { 3 } x - 5 < 23

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Solve and graph. - 22≤8x−222 \leq 8 x - 2 and 5x−7<285 x - 7 < 28  Solve and graph. - 22 \leq 8 x - 2  and  5 x - 7 < 28

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Solve. -In order for a chemical reaction to take place, the Fahrenheit temperature F of the reagents must be at least 184.81∘F184.81 ^ { \circ } \mathrm { F } . At what Celsius temperatures C\mathrm { C } will the reaction occur? (F=95C+32)\left( \mathrm { F } = \frac { 9 } { 5 } \mathrm { C } + 32 \right)

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Solve. - −9<2−10x8≤4- 9 < \frac { 2 - 10 x } { 8 } \leq 4

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