Exam 12: Prerequisites

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Find a point-slope form equation for the line through the point with the given slope. - (4,8),m=2( 4,8 ) , m = 2

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Solve the equation using the quadratic formula. - 7x2+10x+2=07 x ^ { 2 } + 10 x + 2 = 0

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Solve the inequality. - 10≥5x+23≥−510 \geq \frac { 5 x + 2 } { 3 } \geq - 5

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Use an inequality to describe the interval of real numbers. -Use an inequality to describe the interval of real numbers. -

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Solve the equation. - x2+x+5=0x ^ { 2 } + x + 5 = 0

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Find the midpoint of the line segment with the given endpoints. - (−72,−52)\left( - \frac { 7 } { 2 } , - \frac { 5 } { 2 } \right) and (−52,32)\left( - \frac { 5 } { 2 } , \frac { 3 } { 2 } \right)

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Solve the equation by factoring. - x2−x=12x ^ { 2 } - x = 12

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Solve the inequality. Use algebra to solve the corresponding equation. - x2+7≤−2xx ^ { 2 } + 7 \leq - 2 x

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Evaluate the expression. - 7+∣−7∣7 + | - 7 |

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Write the number in decimal form. - 8.096×1078.096 \times 10 ^ { 7 }

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Find the distance between the points. - (7,6)(−5,−5)( 7,6 ) ( - 5 , - 5 )

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Use interval notation to describe the set of numbers. -Every item in Albert's Variety store costs less than $3.51\$ 3.51 .

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Solve the equation using the quadratic formula. - 6x+7=x26 x + 7 = x ^ { 2 }

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Describe and graph the interval of real numbers. - x is positive x \text { is positive }  Describe and graph the interval of real numbers. - x \text { is positive }

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Write the number in decimal form. - 1.375×10−51.375 \times 10 ^ { - 5 }

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Solve the equation. - 25x−13x=5\frac { 2 } { 5 } x - \frac { 1 } { 3 } x = 5

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Use an inequality to describe the interval of real numbers. -Use an inequality to describe the interval of real numbers. -

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Give the quadrant in which the point is located. - (−4,−3)( - 4 , - 3 )

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Write the expression in standard form. - (1−3i)(1+i)1+3i\frac { ( 1 - \sqrt { 3 } i ) ( 1 + i ) } { 1 + \sqrt { 3 } i }

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Use interval notation to describe the interval of real numbers. - xx is greater than or equal to −5- 5 and less than or equal to −1- 1 .

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