Exam 14: Analysis of Categorical Data

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If the test statistic for a chi-squared goodness-of-fit test is larger than the critical value, the null hypothesis should be rejected.

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Medical statistics show that deaths due to four major diseases - call them A, B, C and D - account for 15%, 21%, 18%, and 14%, respectively, of all non-accidental deaths. A study of the causes of 616 non-accidental deaths at a hospital give the following counts: Medical statistics show that deaths due to four major diseases - call them A, B, C and D - account for 15%, 21%, 18%, and 14%, respectively, of all non-accidental deaths. A study of the causes of 616 non-accidental deaths at a hospital give the following counts:   Do these data provide sufficient evidence to indicate that the proportions of people dying of diseases A, B, C, and D at this hospital differ from the proportions accumulated for the population at large? Find the approximate p-value and use it to make your decision. Compute   : ______________ Reject   when   > ______________. Thus the p-value ______________. Conclude that the proportions of people dying of diseases A, B, C, and D at this hospital ______________ from the proportions for the larger population. Do these data provide sufficient evidence to indicate that the proportions of people dying of diseases A, B, C, and D at this hospital differ from the proportions accumulated for the population at large? Find the approximate p-value and use it to make your decision. Compute Medical statistics show that deaths due to four major diseases - call them A, B, C and D - account for 15%, 21%, 18%, and 14%, respectively, of all non-accidental deaths. A study of the causes of 616 non-accidental deaths at a hospital give the following counts:   Do these data provide sufficient evidence to indicate that the proportions of people dying of diseases A, B, C, and D at this hospital differ from the proportions accumulated for the population at large? Find the approximate p-value and use it to make your decision. Compute   : ______________ Reject   when   > ______________. Thus the p-value ______________. Conclude that the proportions of people dying of diseases A, B, C, and D at this hospital ______________ from the proportions for the larger population. : ______________ Reject Medical statistics show that deaths due to four major diseases - call them A, B, C and D - account for 15%, 21%, 18%, and 14%, respectively, of all non-accidental deaths. A study of the causes of 616 non-accidental deaths at a hospital give the following counts:   Do these data provide sufficient evidence to indicate that the proportions of people dying of diseases A, B, C, and D at this hospital differ from the proportions accumulated for the population at large? Find the approximate p-value and use it to make your decision. Compute   : ______________ Reject   when   > ______________. Thus the p-value ______________. Conclude that the proportions of people dying of diseases A, B, C, and D at this hospital ______________ from the proportions for the larger population. when Medical statistics show that deaths due to four major diseases - call them A, B, C and D - account for 15%, 21%, 18%, and 14%, respectively, of all non-accidental deaths. A study of the causes of 616 non-accidental deaths at a hospital give the following counts:   Do these data provide sufficient evidence to indicate that the proportions of people dying of diseases A, B, C, and D at this hospital differ from the proportions accumulated for the population at large? Find the approximate p-value and use it to make your decision. Compute   : ______________ Reject   when   > ______________. Thus the p-value ______________. Conclude that the proportions of people dying of diseases A, B, C, and D at this hospital ______________ from the proportions for the larger population. > ______________. Thus the p-value ______________. Conclude that the proportions of people dying of diseases A, B, C, and D at this hospital ______________ from the proportions for the larger population.

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In a typical contingency-table test, we calculate each expected cell frequency as the product of row total times column total times sample size.

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The following table shows the results of a study in which random samples of 200 members of each of five large unions were asked whether they are for, undecided, or against a certain piece of legislation. The following table shows the results of a study in which random samples of 200 members of each of five large unions were asked whether they are for, undecided, or against a certain piece of legislation.   Use the 0.025 level of significance to test whether the unions differ with respect to their views. Compute   = ______________ Reject   when   > ______________. Conclude: The unions ______________ different views. Use the 0.025 level of significance to test whether the unions differ with respect to their views. Compute The following table shows the results of a study in which random samples of 200 members of each of five large unions were asked whether they are for, undecided, or against a certain piece of legislation.   Use the 0.025 level of significance to test whether the unions differ with respect to their views. Compute   = ______________ Reject   when   > ______________. Conclude: The unions ______________ different views. = ______________ Reject The following table shows the results of a study in which random samples of 200 members of each of five large unions were asked whether they are for, undecided, or against a certain piece of legislation.   Use the 0.025 level of significance to test whether the unions differ with respect to their views. Compute   = ______________ Reject   when   > ______________. Conclude: The unions ______________ different views. when The following table shows the results of a study in which random samples of 200 members of each of five large unions were asked whether they are for, undecided, or against a certain piece of legislation.   Use the 0.025 level of significance to test whether the unions differ with respect to their views. Compute   = ______________ Reject   when   > ______________. Conclude: The unions ______________ different views. > ______________. Conclude: The unions ______________ different views.

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Numbers in a contingency table show the frequency of occurrence of all possible combinations of categories.

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Consumer panel preferences for three proposed fast food restaurants are as follows: Consumer panel preferences for three proposed fast food restaurants are as follows:   Use 0.05 level of significance and test to see if there is a preference among the three restaurants.   = ______________ Critical Value = ______________ Conclusion: ______________ There ______________ preference among the three restaurants. Use 0.05 level of significance and test to see if there is a preference among the three restaurants. Consumer panel preferences for three proposed fast food restaurants are as follows:   Use 0.05 level of significance and test to see if there is a preference among the three restaurants.   = ______________ Critical Value = ______________ Conclusion: ______________ There ______________ preference among the three restaurants. = ______________ Critical Value = ______________ Conclusion: ______________ There ______________ preference among the three restaurants.

(Short Answer)
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In a chi-square test of independence, the value of the test statistic was In a chi-square test of independence, the value of the test statistic was   = 9.572, and the critical value at   was 11.1433. Thus, = 9.572, and the critical value at In a chi-square test of independence, the value of the test statistic was   = 9.572, and the critical value at   was 11.1433. Thus, was 11.1433. Thus,

(Multiple Choice)
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A market research study was conducted to compare three different brands of car oil. The results of the study are summarized below. A market research study was conducted to compare three different brands of car oil. The results of the study are summarized below.   Use the accompanying MINITAB output and   = 0.005 to determine whether the brand of oil is independent of opinion. Compute   = ______________ Reject   when   > ______________. Conclude that the two variables are ______________. Use the accompanying MINITAB output and A market research study was conducted to compare three different brands of car oil. The results of the study are summarized below.   Use the accompanying MINITAB output and   = 0.005 to determine whether the brand of oil is independent of opinion. Compute   = ______________ Reject   when   > ______________. Conclude that the two variables are ______________. = 0.005 to determine whether the brand of oil is independent of opinion. Compute A market research study was conducted to compare three different brands of car oil. The results of the study are summarized below.   Use the accompanying MINITAB output and   = 0.005 to determine whether the brand of oil is independent of opinion. Compute   = ______________ Reject   when   > ______________. Conclude that the two variables are ______________. = ______________ Reject A market research study was conducted to compare three different brands of car oil. The results of the study are summarized below.   Use the accompanying MINITAB output and   = 0.005 to determine whether the brand of oil is independent of opinion. Compute   = ______________ Reject   when   > ______________. Conclude that the two variables are ______________. when A market research study was conducted to compare three different brands of car oil. The results of the study are summarized below.   Use the accompanying MINITAB output and   = 0.005 to determine whether the brand of oil is independent of opinion. Compute   = ______________ Reject   when   > ______________. Conclude that the two variables are ______________. > ______________. Conclude that the two variables are ______________.

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A chi-square test of independence is applied to a contingency table with 4 rows and 5 columns for two qualitative variables. The degrees of freedom for this test will be:

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A goodness-of-fit test determines the likelihood that sample data have been generated from a population that conforms to a specified type of probability distribution.

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If we want to conduct a one-tail test of a population proportion, we can employ:

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Consider a cell in a contingency table. Given the cell's row total of 80, the cell's column total of 60, and a sample size of 250, the cell's expected frequency:

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The chi-square test of a contingency table is based upon:

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A chi-square test for independence is applied to a contingency table with 4 rows and 4 columns for two qualitative variables. The degrees of freedom for this test must be 9.

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The sampling distribution of the test statistic for a goodness-of-fit test with k categories is:

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The degrees of freedom associated with a contingency-table test of independence equal the number of rows times the number of columns in the table.

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