Exam 4: Elementary Number Theory and Methods of Proof

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Use the Euclidean algorithm to find the greatest common divisor of 284 and 168. Show your work.

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Prove the following statement directly from the definitions of the terms. Do not use any other facts previously proved in class or in the text or in the exercises.  For all rational numbers r, and s, if s≠0, then 2r5s is a rational number. \text { For all rational numbers } r \text {, and } s \text {, if } s \neq 0 \text {, then } \frac { 2 r } { 5 s } \text { is a rational number. }

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Proof: Suppose rr and ss , are any rational numbers with s≠0s \neq 0 . // We must show that 2r5s\frac { 2 r } { 5 s } is a rational number./By definition of rational, there exist integers a,b,ca , b , c , and dd with b≠0b \neq 0 and d≠0d \neq 0 such that
r=ab and s=cdr = \frac { a } { b } \quad \text { and } \quad s = \frac { c } { d }
In addition, since c=s⋅dc = s \cdot d and since neither ss nor dd equals 0 , then c≠0c \neq 0 by the zero product property. Then
2r5s=2⋅ab5⋅cd=2ad5bc\frac { 2 r } { 5 s } = \frac { 2 \cdot \frac { a } { b } } { 5 \cdot \frac { c } { d } } = \frac { 2 a d } { 5 b c }
Now both 2ad2 a d and 5bc5 b c are integers because they are products of integers, and 5bc≠05 b c \neq 0 by the zero product property. Hence 2r5s\frac { 2 r } { 5 s } is a ratio of integers with a nonzero denominator, and so 2r5s\frac { 2 r } { 5 s } is a rational number by definition of rational [as was to be shown].

State precisely (but concisely) what it means for an integer n to be odd.

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Some acceptable answers:
a. An integer n is odd if, and only if, n = 2k + 1 for some integer k.
b. An integer n is odd if, and only if, n equals 2 times some integer plus 1.
c. An integer n is odd if, and only if, there exists an integer m such that n = 2m +1 .

Outline a proof of the following statement by writing the "starting point" and the "conclusion to be shown" in a proof of the statement. ∀ real numbers r and s, if r and s are rational then r−s is rational. \forall \text { real numbers } r \text { and } s \text {, if } r \text { and } s \text { are rational then } r - s \text { is rational. } That is, complete the sentences below. Proof: Suppose______ We must show that__________

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Prove the following statement: The sum of any two consecutive integers can be written in the form 4n + 1 for some integer n.

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Prove the following statement directly from the definitions of the terms. Do not use any other facts previously proved in class or in the text or in the exercises.  For all integers a,b, and c, if a∣b and a∣c, then a∣(5b+3c). \text { For all integers } a , b \text {, and } c \text {, if } a \mid b \text { and } a \mid c \text {, then } a \mid ( 5 b + 3 c ) \text {. }

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Prove the following statement: There is no smallest positive rational number.

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 If m and n are integers, is 6m2+34n−18 an even integer?\text { If } m \text { and } n \text { are integers, is } 6 m ^ { 2 } + 34 n - 18 \text { an even integer?} Justify your answer

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Is 56.745 a rational number? Justify your answer.

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True or false? For any irrational number r, r2 is irrational. Justify your answer.

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Show that the following statement is false: The product of any two irrational numbers is irrational.

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State precisely (but concisely) what it means for an integer n to be divisible by an integer d.

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Does 12 divide 72? Justify your answer.

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Prove the following statement by contradiction: For all real numbers r and s, if r is rational and s is irrational, then r + 2s is irrational.

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Prove by contradiction that 4+32 4 + 3 \sqrt { 2 } \text { } is an irrational number. (You may use the fact that } 2\sqrt { 2 } is irrational.

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State precisely (but concisely) what it means for a number r to be rational.

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Fill in the blanks of the following proof by contradiction that 7+427 + 4 \sqrt { 2 } is an irrational number. (You may use the fact that 2\sqrt { 2 } is irrational.) Proof: Suppose not. That is, suppose that 7+427 + 4 \sqrt { 2 } is (i). By definition of rational, 7+42=7 + 4 \sqrt { 2 } = ab\frac { a } { b } , where (ii). Multiplying both sides by bb gives 7b+4b2=a,7 b + 4 b \sqrt { 2 } = a , so if we subtract 7b7 b from both sides we have 4b2= (iii) ‾.4 b \sqrt { 2 } = \underline { \text { (iii) } } . Dividing both sides by 4b4 b gives 2= (iv). \sqrt { 2 } = \text { (iv). } But then 2\sqrt { 2 } would be a rational number because (v). This contradicts our knowledge that 2\sqrt { 2 } is irrational. Hence (vi).

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Prove the following statement directly from the definition of divisibility. Do not use any other facts previously proved in class or in the text or in the exercises.For all integers aa , and bb , if aa divides bb then a3a ^ { 3 } divides b3b ^ { 3 } .

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Consider the following statement:  Statement A: ∀ integers m and n, if 2m+n is odd then m and n are both odd. \text { Statement A: } \forall \text { integers } m \text { and } n \text {, if } 2 m + n \text { is odd then } m \text { and } n \text { are both odd. } (a) Write a negation for Statement A. (b) Disprove Statement A. That is, show that Statement A is false.

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Consider the following statement: For all integers n, if n3 is even then n is even. (a) Prove the statement either by contradiction or by contraposition. Clearly indicate which method you are using. (b) If you used proof by contradiction in part (a), write what you would "suppose" and what you would "show" to prove the statement by contraposition. If you used proof by contraposition. in part (a), write what you would "suppose" and what you would "show" to prove the statement by contradiction.

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