Exam 20: Magnetism

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A straight bar magnet is initially 4 cm long, with the north pole on the right and the south pole on the left. If you cut the magnet in half, the right half will

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How much current must flow through a long straight wire for the magnetic field strength to be 1.01.0 mT\mathrm { mT } at 1.0 cm1.0 \mathrm {~cm} from a wire? (μ0=4π×10−7 T⋅m/A)\left( \mu _ { 0 } = 4 \pi \times 10 ^ { - 7 } \mathrm {~T} \cdot \mathrm { m } / \mathrm { A } \right)

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A proton, moving in a uniform magnetic field, moves in a circle perpendicular to the field lines and takes time T for each circle. If the proton's speed tripled, what would now be its time to go around Each circle?

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If you were to cut a small permanent bar magnet in half,

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When two long parallel wires carry unequal currents, the magnitude of the magnetic force that one wire exerts on the other is F. If the current in both wires is now doubled, what is the magnitude of The new magnetic force on each wire?

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An electron is moving to the right, as shown in the figure. Suddenly it encounters uniform magnetic field pointing out of the page. Which one of the three paths shown will it follow in the field? An electron is moving to the right, as shown in the figure. Suddenly it encounters uniform magnetic field pointing out of the page. Which one of the three paths shown will it follow in the field?

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An electron has an initial velocity to the south but is observed to curve upward as the result of a magnetic field. This magnetic field must have a component

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A proton travels at a speed of 5.0×107 m/s5.0 \times 10 ^ { 7 } \mathrm {~m} / \mathrm { s } through a 1.0−T1.0 - \mathrm { T } magnetic field. What is the magnitude of the magnetic force on the proton if the angle between the proton's velocity and the magnetic field vector is 30∘?(e=1.60×10−19C)30 ^ { \circ } ? \left( e = 1.60 \times 10 ^ { - 19 } \mathrm { C } \right)

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Which one of the following statements is correct?

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A proton moving with a velocity of 4.0×104 m/s4.0 \times 10 ^ { 4 } \mathrm {~m} / \mathrm { s } enters a magnetic field of 0.20 T0.20 \mathrm {~T} . If the angle between the velocity of the proton and the direction of the magnetic field is 60∘60 ^ { \circ } , what is the magnitude of the magnetic force on the proton? (e=1.60×10−19C)\left( e = 1.60 \times 10 ^ { - 19 } \mathrm { C } \right)

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A long, straight, horizontal wire carries current toward the east. A proton moves toward the east alongside and just south of the wire. What is the direction of the magnetic force on the proton?

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A particle carrying a charge of +e travels in a circular path of radius R in a uniform magnetic field. If instead the particle carried a charge of +2e, the radius of the circular path would have been

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The magnetic field due to the current in a long, straight wire is 8.0μT8.0 \mu T at a distance of 4.0 cm4.0 \mathrm {~cm} from the center of the wire. What is the current in the wire? (μ0=4π×10−7 T⋅m/A)\left( \mu _ { 0 } = 4 \pi \times 10 ^ { - 7 } \mathrm {~T} \cdot \mathrm { m } / \mathrm { A } \right)

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A charged particle of mass 0.0040 kg is subjected to a 4.0-T magnetic field which acts at a right angle to its motion. If the particle moves in a circle of radius 0.10 m at a speed of 2.0 m/s, what is The magnitude of the charge on the particle?

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In a mass spectrometer, a single-charged particle has a speed of 1.00×106 m/s1.00 \times 10 ^ { 6 } \mathrm {~m} / \mathrm { s } and enters a uniform magnetic field of 0.200 T0.200 \mathrm {~T} at a right angle to the field. The radius of the resulting circular orbit is 20.75 cm20.75 \mathrm {~cm} . What is the mass of the particle? (e=1.60×10−19C)\left( e = 1.60 \times 10 ^ { - 19 } \mathrm { C } \right)

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A very long straight current-carrying wire produces a magnetic field of 20mT20 \mathrm { mT } at a distance dd from the wire. To measure a field of 5mT5 \mathrm { mT } due to this wire, you would have to go to a distance from the wire of

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A flat rectangular loop of wire is placed between the poles of a magnet, as shown in the figure. It has dimensions w=0.60 mw = 0.60 \mathrm {~m} and L=1.0 mL = 1.0 \mathrm {~m} , and carries a current I=2.0 AI = 2.0 \mathrm {~A} in the direction shown. The magnetic field due to the magnet is uniform and of magnitude 0.80 T0.80 \mathrm {~T} . The loop rotates in the magnetic field and at one point the plane of the loop is perpendicular to the field. At that instant, what is the magnitude of the torque acting on the wire due to the magnetic field?  A flat rectangular loop of wire is placed between the poles of a magnet, as shown in the figure. It has dimensions  w = 0.60 \mathrm {~m}  and  L = 1.0 \mathrm {~m} , and carries a current  I = 2.0 \mathrm {~A}  in the direction shown. The magnetic field due to the magnet is uniform and of magnitude  0.80 \mathrm {~T} . The loop rotates in the magnetic field and at one point the plane of the loop is perpendicular to the field. At that instant, what is the magnitude of the torque acting on the wire due to the magnetic field?

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In the figure, a rectangular current loop is carrying current I1=7.0 AI _ { 1 } = 7.0 \mathrm {~A} , in the direction indicated, near a long wire carrying a current IWI _ { \mathbf { W } } . The long wire is parallel to the sides of the rectangle. The rectangle loop has length 0.80 m0.80 \mathrm {~m} and its sides are 0.10 m0.10 \mathrm {~m} and 0.70 m0.70 \mathrm {~m} from the wire. If the net force on the loop is to have magnitude 1.7×10−6 N1.7 \times 10 ^ { - 6 } \mathrm {~N} and is to be directed towards the wire, what must be the magnitude and direction (from top to bottom or from bottom to top in the sketch) of the current IWI _ { W } in the wire? (μ0=4π×10−7 T\left( \mu _ { 0 } = 4 \pi \times 10 ^ { - 7 } \mathrm {~T} \right. . m/A)\mathrm { m } / \mathrm { A } )  In the figure, a rectangular current loop is carrying current  I _ { 1 } = 7.0 \mathrm {~A} , in the direction indicated, near a long wire carrying a current  I _ { \mathbf { W } } . The long wire is parallel to the sides of the rectangle. The rectangle loop has length  0.80 \mathrm {~m}  and its sides are  0.10 \mathrm {~m}  and  0.70 \mathrm {~m}  from the wire. If the net force on the loop is to have magnitude  1.7 \times 10 ^ { - 6 } \mathrm {~N}  and is to be directed towards the wire, what must be the magnitude and direction (from top to bottom or from bottom to top in the sketch) of the current  I _ { W }  in the wire?  \left( \mu _ { 0 } = 4 \pi \times 10 ^ { - 7 } \mathrm {~T} \right. .  \mathrm { m } / \mathrm { A } )

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In the figure, a small particle of charge −1.9×10−6C- 1.9 \times 10 ^ { - 6 } \mathrm { C } and mass m=3.1×10−12 kgm = 3.1 \times 10 ^ { - 12 } \mathrm {~kg} has speed v0=8.1×103 m/sv _ { 0 } = 8.1 \times 10 ^ { 3 } \mathrm {~m} / \mathrm { s } as it enters a region of uniform magnetic field. The particle is initially traveling perpendicular to the magnetic field and is observed to travel in the semicircular path shown with radius R=5.0 cmR = 5.0 \mathrm {~cm} . Find the magnitude and direction of the magnetic field in the region.  In the figure, a small particle of charge  - 1.9 \times 10 ^ { - 6 } \mathrm { C }  and mass  m = 3.1 \times 10 ^ { - 12 } \mathrm {~kg}  has speed  v _ { 0 } = 8.1 \times 10 ^ { 3 } \mathrm {~m} / \mathrm { s }  as it enters a region of uniform magnetic field. The particle is initially traveling perpendicular to the magnetic field and is observed to travel in the semicircular path shown with radius  R = 5.0 \mathrm {~cm} . Find the magnitude and direction of the magnetic field in the region.

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We observe that a moving charged particle experiences no magnetic force. From this we can definitely conclude that

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