Exam 28: Quantum Mechanics of Atoms

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How many electrons can be found with principal quantum number n = 3 in a suitably heavy atom?

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A tiny dust particle of mass 8.50μg8.50 \mu \mathrm { g } is being observed under a microscope. Its position is determined to be within a space of 0.0060 mm0.0060 \mathrm {~mm} . ( h=6.626×10−34 J⋅sh = 6.626 \times 10 ^ { - 34 } \mathrm {~J} \cdot \mathrm { s } ) (a) Find the uncertainty in its speed implied by the uncertainty in its position. (b) Assuming the dust particle is moving at the speed in part (a), how many years would it take for the particle to move 1.0 mm1.0 \mathrm {~mm} ?

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The only invalid electron state and shell designation among the following is

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In a hydrogen atom, a given electron has n = 7. How many possible values can ʆ have?

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According to Pauli's exclusion principle, how many electrons in an atom may have a particular set of quantum numbers?

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A baseball has mass 143 g143 \mathrm {~g} and a speed of 45 m/s45 \mathrm {~m} / \mathrm { s } , with the speed known to within 0.10%0.10 \% . What is the minimum uncertainty in the position of the baseball? (h=6.626×10−34 J⋅s)\left( h = 6.626 \times 10 ^ { - 34 } \mathrm {~J} \cdot \mathrm { s } \right)

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For an electron in the M (n=3)( n = 3 ) shell, find (a) the largest possible orbital angular momentum it can have, and (b) the smallest possible orbital angular momentum it can have. Express your answers in SI units, and for each case indicate the subshell (s,p,d,…)( s , p , d , \ldots ) of the electron. (h=6.626×10−34 J⋅s)\left( h = 6.626 \times 10 ^ { - 34 } \mathrm {~J} \cdot \mathrm { s } \right)

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Write out the electron configuration for the ground state of the phosphorus atom, which has 15 electrons.

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What is the minimum uncertainty in determining the position of an electron if the speed of the electron is 6.0 km/s6.0 \mathrm {~km} / \mathrm { s } within an accuracy of 0.0040%0.0040 \% ? (melectron =9.11×10−31 kg,h=6.626×10−34= 9.11 \times 10 ^ { - 31 } \mathrm {~kg} , h = 6.626 \times 10 ^ { - 34 } J⋅s)\mathrm { J } \cdot \mathrm { s } )

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According to the quantum mechanical model of the hydrogen atom, if the principal quantum number is n, how many different orbital angular momentum quantum numbers are permitted?

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Suppose that the speed of an electron traveling 2.0 km/s2.0 \mathrm {~km} / \mathrm { s } is known to an accuracy of 1 part in 10510 ^ { 5 } (i.e., within 0.0010%0.0010 \% ). What is the least possible uncertainty within which we can determine the position of this electron? ( melectron =9.11×10−31 kg,h=6.626×10−34 J⋅s)\left. m _ { \text {electron } } = 9.11 \times 10 ^ { - 31 } \mathrm {~kg} , h = 6.626 \times 10 ^ { - 34 } \mathrm {~J} \cdot \mathrm { s } \right)

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A hydrogen atom is in the 6h state. Which one of the following is not a magnetic quantum number for that state?

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What is the electron configuration for Li, which has 3 electrons?

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The magnetic quantum number m1 can have any integer value ranging from

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What is the maximum number of electrons that can occupy the g subshell?

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What is the greatest magnitude of the orbital angular momentum LL that you can find in a state with n=6n = 6 ?

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How many values of the magnetic quantum number, mʆ, correspond to a value of ʆ = 4?

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A hydrogen atom is in the 6h state. What is the principal quantum number.

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Neon has 10 electrons. What is the value of ZZ of the next higher element that has chemical properties very similar to those of neon?

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If you confine an electron to a box and know that the uncertainty in the electron's speed is 65 m/s65 \mathrm {~m} / \mathrm { s } , what is the smallest length that the box could have? (melectron =9.11×10−31 kg,h=6.626×10−34= 9.11 \times 10 ^ { - 31 } \mathrm {~kg} , h = 6.626 \times 10 ^ { - 34 } J.s)

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