Exam 8: More on Functions and Graphs

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Solve the problem. -Sales for a small clothing company can be modeled by the linear function S(x) = 4200x + 57,400, where x is the number of years since 2005 and S(x) is in dollars. Predict the first whole year that Sales will exceed $120,000.

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Find the domain and range of the relation. Also determine whether the relation is a function. -Find the domain and range of the relation. Also determine whether the relation is a function. -

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Graph the function. State the domain and range of the function. - f(x)=x2+4f(x)=x^{2}+4  Graph the function. State the domain and range of the function. - f(x)=x^{2}+4

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Find an equation of the line. Write the equation using function notation. -Through (2,3)( 2,3 ) ; perpendicular to f(x)=4x−2f ( x ) = 4 x - 2

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Solve. -When the temperature stays the same, the volume of a gas is inversely proportional to the pressure of the gas. If a balloon is filled with 294 cubic inches of a gas at a pressure of 14 pounds per square Inch, find the new pressure of the gas if the volume is decreased to 42 cubic inches.

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Write an equation to describe the variation. Use k for the constant of proportionality. - s\mathrm { s } varies directly as t\mathrm { t } and inversely as the square of u\mathrm { u } .

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Graph the function. - f(x)=x−5f ( x ) = \sqrt { x - 5 }  Graph the function. - f ( x ) = \sqrt { x - 5 }

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Graph the piecewise defined function. - f(x)={x+5 if x<1−4 if x≥1f ( x ) = \left\{ \begin{array} { l l } x + 5 & \text { if } x < 1 \\- 4 & \text { if } x \geq 1\end{array} \right.  Graph the piecewise defined function. - f ( x ) = \left\{ \begin{array} { l l }  x + 5 & \text { if } x < 1 \\ - 4 & \text { if } x \geq 1 \end{array} \right.

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Use function notation to write the equation of the line with the given slope and y-intercept. -Slope 43;y\frac { 4 } { 3 } ; y -intercept (0,−1)( 0 , - 1 )

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Fill in the blank with one of the words or phrases listed below. slope-intercept directly slope jointly parallel perpendicular function inversely linear function -In the equation y=kx\mathrm { y } = \frac { \mathrm { k } } { \mathrm { x } } , y\mathrm { y } varies_______ as XX .

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Graph the function. - f(x)=−∣x∣+2f(x)=-|x|+2  Graph the function. - f(x)=-|x|+2

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Find the variation equation for the variation statement. - yy varies directly as the square of x;y=−815x ; y = - \frac { 81 } { 5 } when x=9x = 9

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Graph the function. State the domain and range of the function. - f(x)={4x+1 if x≤012x−4 if x>0f ( x ) = \left\{ \begin{array} { l l } 4 x + 1 & \text { if } x \leq 0 \\ \frac { 1 } { 2 } x - 4 & \text { if } x > 0 \end{array} \right.  Graph the function. State the domain and range of the function. - f ( x ) = \left\{ \begin{array} { l l } 4 x + 1 & \text { if } x \leq 0 \\ \frac { 1 } { 2 } x - 4 & \text { if } x > 0 \end{array} \right.

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Graph the function. - f(x)=−x−1f(x)=-\sqrt{x}-1  Graph the function. - f(x)=-\sqrt{x}-1

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Find an equation of the line satisfying the given conditions. Write the equation in standard form. -Horizontal; through (−4,−2)( - 4 , - 2 )

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Find the equation of the line. Write the equation using standard notation. -Through (10,−10)( 10 , - 10 ) ; perpendicular to y=8\mathrm { y } = 8

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Graph the function. - f(x)=(x−7)2+5f(x)=(x-7)^{2}+5  Graph the function. - f(x)=(x-7)^{2}+5

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Solve. -Suppose that QQ is jointly proportional to RR and the square of SS . If Q=16Q = 16 when R=2R = 2 and S=2S = 2 , find Q when R=6R = 6 and S=3S = 3 .

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Find an equation of the line with the given slope and containing the given point. Write the equation using function notation. -Slope 43;\frac { 4 } { 3 } ; through (0,2)( 0,2 )

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Graph the function. - f(x)=−x2−4f(x)=-x^{2}-4  Graph the function. - f(x)=-x^{2}-4

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