Exam 5: Inverse, Exponential, and Logarithmic Functions

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Write an equation for the graph given. The graph represents an logarithmic function f with base 2 or 3, translated and/or reflected. -Write an equation for the graph given. The graph represents an logarithmic function f with base 2 or 3, translated and/or reflected. -

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Use properties of logarithms to evaluate the expression. - log⁡10(0.0001)9\log _ { 10 } ( 0.0001 ) ^ { 9 }

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Decide whether the given functions are inverses. -Decide whether the given functions are inverses. -

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Why can't 1 be the base of a logarithmic function?

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 Explain how the graph of y=log⁡2(x−5) can be obtained from the graph of y=log⁡2x. \text { Explain how the graph of } y = \log _ { 2 } ( x - 5 ) \text { can be obtained from the graph of } y = \log _ { 2 } x \text {. }

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Find the domain and range of the inverse of the given function. - f(x)=5−x2;x≥0f ( x ) = 5 - x ^ { 2 } ; x \geq 0

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Write an equivalent expression in exponential form. - log⁡53125=x\log 53125 = x

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 Explain how the graph of y=log⁡2x7 can be obtained from the graph of y=log⁡2x. \text { Explain how the graph of } y = \log _ { 2 } \frac { x } { 7 } \text { can be obtained from the graph of } y = \log _ { 2 } x \text {. }

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Write the algebraic equation which can be used to find the exact solution of log3 (x−6)+log⁡3(x−1)=2( x - 6 ) + \log _ { 3 } ( x - 1 ) = 2 .

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Find the value. Give an approximation to four decimal places. -log 0.0820

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Find the domain and range of the inverse of the given function. - f(x)=x3−2f ( x ) = x ^ { 3 } - 2

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Find the domain and range of the inverse of the given function. - f(x)=x−2f ( x ) = \sqrt { x - 2 }

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Use a graphing calculator to estimate the solution set of the equation. Round to the nearest hundredth. - 2(x−1)=172 ^ { ( x - 1 ) } = 17

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Evaluate the logarithm. - log⁡10100\log _ { 10 } 100

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Solve the following graphically. If necessary, round answers to the nearest thousandth. - ln⁡(x−2)=−x+13\ln ( x - 2 ) = - \sqrt [ 3 ] { x + 1 }

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In a town whose population is 3000, a disease creates an epidemic. The number N of people infected t days after the disease has begun is given by the function N N(t)=30001+21.5⋅e−0.5t\mathrm { N } ( \mathrm { t } ) = \frac { 3000 } { 1 + 21.5 \cdot \mathrm { e } ^ { - 0.5 \mathrm { t } } } . Find the number infected after 8 days.

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Solve the equation. - 4−x=1164 ^ { - x } = \frac { 1 } { 16 }

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A lake is stocked with 545 fish of a new variety. The size of the lake, the availability of food, and the number of other fish restrict growth in the lake to a limiting value of 3406. The population of fish in the lake after time t, in Months, is given by the function P(t) P(t)=34061+5.07e−0.25tP ( t ) = \frac { 3406 } { 1 + 5.07 e ^ { - 0.25 t } } . After how many months will the population be 2405?

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Write an equivalent expression in exponential form. - log⁡1/2(x+6)=−7\log _ { 1 / 2 } ( x + 6 ) = - 7

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Given log⁡102≈0.3010 and log⁡103≈0.4771\log _ { 10 } 2 \approx 0.3010 \text { and } \log _ { 10 } 3 \approx 0.4771 find the logarithm without using a calculator. - log⁡10(181/3)\log _ { 10 } \left( 18 ^ { 1 / 3 } \right)

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