Exam 4: Number Theory and Cryptography

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Find adiv⁡m and a mod m when a=511,m=113a \operatorname { div } m \text { and } a \bmod m \text { when } a = 511 , m = 113

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find the sum and product of each of these pairs of numbers. Express your answer as a hexadecimal expansion. - (E3 A)16,( B5 F8)16( \mathrm { E } 3 \mathrm {~A} ) _ { 16 } , ( \mathrm {~B} 5 \mathrm {~F} 8 ) _ { 16 }

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Use the Euclidean Algorithm to find gcd(390, 72).

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Find the prime factorization of 8,827.

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Use the Vigen`ere cipher with key NOW to encrypt the message SUMMER.

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Convert (10,000)10 to base 2.

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Solve the linear congruence 54x≡12( mod 73) given that the inverse of 54 modulo 73 is 23. 54 x \equiv 12 ( \bmod 73 ) \text { given that the inverse of } 54 \text { modulo } 73 \text { is } 23 \text {. }

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Prove: if n is an integer that is not a multiple of 4,  then n2≡0 mod 4 or n2≡1 mod 4. \text { then } n ^ { 2 } \equiv 0 \bmod 4 \text { or } n ^ { 2 } \equiv 1 \bmod 4 \text {. }

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What does a 60-second stop watch read 82 seconds after it reads 27 seconds?

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Find the integer a such that a=71( mod 41) and 160≤a≤200a = 71 ( \bmod 41 ) \text { and } 160 \leq a \leq 200

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Solve the linear congruence 2x≡5( mod 9)2 x \equiv 5 ( \bmod 9 )

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suppose that a and b are integers, a≡4( mod 7), and b≡6( mod 7). Find the integer c with 0≤c≤6a \equiv 4 ( \bmod 7 ) , \text { and } b \equiv 6 ( \bmod 7 ) . \text { Find the integer } c \text { with } 0 \leq c \leq 6 such that - c≡5b( mod 7)c \equiv 5 b ( \bmod 7 )

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What does a 60-second stop watch read 54 seconds before it reads 19 seconds?

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Encrypt the message NEED HELP by translating the letters into numbers (A=0, B=1, . . ., Z=25), applying the encryption function f(p)=(3p+7) mod 26f ( p ) = ( 3 p + 7 ) \bmod 26 and then translating the numbers back into letters.

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suppose that a and b are integers, a≡4( mod 7), and b≡6( mod 7). Find the integer c with 0≤c≤6a \equiv 4 ( \bmod 7 ) , \text { and } b \equiv 6 ( \bmod 7 ) . \text { Find the integer } c \text { with } 0 \leq c \leq 6 such that - c≡a2−b2( mod 7)c \equiv a ^ { 2 } - b ^ { 2 } ( \bmod 7 )

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Prove: if n is an integer that is not a multiple of 3,  then n2≡1 mod 3\text { then } n ^ { 2 } \equiv 1 \bmod 3

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Express gcd(450, 120) as a linear combination of 120 and 450.

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Find the discrete logarithms of 5 and 8 to the base 7 modulo 13.

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Encrypt the message BALL using the RSA system with n=37⋅73n = 37 \cdot 73 and e=7e = 7 , translating each letter into integers (A=00, B=01,…)( \mathrm { A } = 00 , \mathrm {~B} = 01 , \ldots ) and grouping together pairs of integers.

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Encode the message "stop at noon" using the function f(x)=(x+6) mod 26f ( x ) = ( x + 6 ) \bmod 26

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