Exam 11: P Prerequisites

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Write the complex number 7+4i4−3i\frac{7+4 i}{4-3 i} in standard form.

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Solve: x2−2x−2<1x^{2}-2 x-2<1

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Find the midpoints of the sides of the triangle defined by the vertices (5, 5), (-2, 7), and (-1, 1).

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In the x y -plane, what is the slope and y -intercept of the graph of the line 4 x+3 y=12 ?

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Which of the following are solutions of the equation (x-5)(x+3)=0?

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Solve graphically: ∣3+5x∣=7|3+5 x|=7

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Solve 2x2+7x−15=02 x^{2}+7 x-15=0 using the quadratic formula.

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Solve the inequality x2−x−6≤0x^{2}-x-6 \leq 0 Express your answer in interval notation.

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Solve −6≤2x+14≤6-6 \leq \frac{2 x+1}{4} \leq 6 algebraically.

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Write the equation of a line through the point (-1,2) and parallel to the line with equation 3 x-2 y-5=0 . Write the equation in the general form.

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Find the distance between the points (-8, 5) and (3, 2).

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Write the inequality that describes the graph. Write the inequality that describes the graph.

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Solve graphically: 4x3−2x2−4x−1=04 x^{3}-2 x^{2}-4 x-1=0

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This year a news agency purchased a delivery vehicle for $27,000 \$ 27,000 . The vehicle's value will depreciate $4,500 \$ 4,500 a year for each of the next 6 years. The equation y=27,000−4,500x,0≤x≤6 y=27,000-4,500 x, 0 \leq x \leq 6 models the vehicle's value, where y y is the value of the vehicle and x x is the number of years after purchase. In how many years will the value of the vehicle be $13,500 \$ 13,500 ?

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Write the complex number 6−5i4+2i\frac{6-5 i}{4+2 i} in standard form.

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Use the quadratic formula to solve 4x2+6x+7=04 x^{2}+6 x+7=0

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Solve the inequality ∣2x+3∣≥1 |2 x+3| \geq 1 algebraically. Write the solution in interval notation and draw its number line graph.  Solve the inequality   |2 x+3| \geq 1   algebraically. Write the solution in interval notation and draw its number line graph.

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Solve: ∣x+12∣>4\left|\frac{x+1}{2}\right|>4

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Which of the following is the graph of x=-5 in the xy-plane?

(Multiple Choice)
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Find the equation of a line that contains (3, 4) and has slope 2. Write the equation in point-slope form.

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