Exam 15: Chi-Squared Tests

arrow
  • Select Tags
search iconSearch Question
flashcardsStudy Flashcards
  • Select Tags

The rule of ____________________ states that in order to conduct the chi-squared goodness-of-fit test, the expected value for each cell must be ____________________ or more.

(Short Answer)
4.9/5
(81)

In conducting a chi-squared goodness-of-fit test, an essential condition is that all expected frequencies are at least five.

(True/False)
4.9/5
(74)

In a test of a contingency table, rejecting the null hypothesis concludes the variables are not independent.

(True/False)
5.0/5
(89)

What statistic do we get when we square the value of z?

(Essay)
4.8/5
(70)

The squared difference between the observed and expected frequencies should be large if there is a significant difference between the proportions.

(True/False)
4.8/5
(75)

If the expected frequency ei for any cell i is less than 5, we should:

(Multiple Choice)
4.9/5
(92)

The owner of a consumer products company asked a random sample of employees how they felt about the work they were doing.The following table gives a breakdown of their responses by age.Is there sufficient evidence to conclude that the level of job satisfaction is related to age? Use α\alpha = .10.  The owner of a consumer products company asked a random sample of employees how they felt about the work they were doing.The following table gives a breakdown of their responses by age.Is there sufficient evidence to conclude that the level of job satisfaction is related to age? Use  \alpha = .10.

(Essay)
4.7/5
(79)

For comparing two or more populations each having two or more categories, use a(n) ____________________ test of a(n) ____________________.

(Short Answer)
4.9/5
(87)

We can use the goodness-of-fit test to determine whether data were drawn from any distribution of interest.The most common application of this procedure is a test of ____________________.

(Short Answer)
4.9/5
(78)

If you want to describe a population with more than two categories, which test(s) can you use?

(Essay)
4.8/5
(81)

If you want to compare two populations that each have two categories, which test(s) can you use?

(Essay)
4.9/5
(79)

The total of the observed frequencies in a multinomial experiment must equal nk where n is the number of trials and k is the number of categories.

(True/False)
4.8/5
(71)

Seat Belts A study was conducted to determine whether the use of seat belts in vehicles depends on whether or not a child was present in the car.A sample of 1,000 people treated for injuries sustained from vehicle accidents was obtained, and each person was classified according to (1) child present (yes/no) and (2) seat belt usage (worn or not worn) during the accident.The data are shown in the table below. Seat Belts A study was conducted to determine whether the use of seat belts in vehicles depends on whether or not a child was present in the car.A sample of 1,000 people treated for injuries sustained from vehicle accidents was obtained, and each person was classified according to (1) child present (yes/no) and (2) seat belt usage (worn or not worn) during the accident.The data are shown in the table below.    -{Seat Belts Narrative} Prepare the table of expected values. -{Seat Belts Narrative} Prepare the table of expected values.

(Essay)
4.7/5
(77)

The expected frequency for the cell in row i and column j is the row i total plus the row j total, all divided by n.

(True/False)
4.8/5
(73)

If we want to perform a two-tail test of a population proportion p, we can only use the z-test of p.

(True/False)
4.9/5
(92)

The rule of five states that in order to conduct the chi-squared goodness-of-fit test, the ____________________ value for each cell must be five or more.

(Short Answer)
4.8/5
(81)

The test statistic for the chi-squared test of a contingency table is the same as the test statistic for the goodness-of-fit test.

(True/False)
5.0/5
(89)

The chi-squared goodness-of-fit test compares the ____________________ frequencies in the table to the ____________________ frequencies based on the null hypothesis.

(Short Answer)
4.7/5
(84)

A chi-squared test is used to describe a population of nominal data.

(True/False)
4.9/5
(59)

If we want to test for differences between two populations of nominal data with exactly two categories, we can employ either the z-test of p1 - p2, or the chi-squared test of a contingency table.

(True/False)
4.7/5
(76)
Showing 141 - 160 of 175
close modal

Filters

  • Essay(0)
  • Multiple Choice(0)
  • Short Answer(0)
  • True False(0)
  • Matching(0)