Exam 12: Analysis of Variance

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If the endpoints of a confidence interval for the difference between a pair of treatment means are both positive numbers,then we reject the null hypothesis that there is no difference in the pair of treatment means.

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What are the minimum and maximum of values of an F distribution? _______ and _______

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For the hypothesis test, For the hypothesis test,   ,with n<sub>1</sub> = 10 and n<sub>2</sub> = 10,the F-test statistic is 2.56.At the 0.01 level of significance,we would reject the null hypothesis. ,with n1 = 10 and n2 = 10,the F-test statistic is 2.56.At the 0.01 level of significance,we would reject the null hypothesis.

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One characteristic of the F distribution is that F cannot be negative.

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Two accounting professors decided to compare the variance of their grading procedures.To accomplish this they each graded the same 10 exams with the following results: Two accounting professors decided to compare the variance of their grading procedures.To accomplish this they each graded the same 10 exams with the following results:   What are the degrees of freedom for the denominator of the F ratio? What are the degrees of freedom for the denominator of the F ratio?

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A manufacturer of automobile transmissions uses three different processes.Management ordered a study of the production costs to see if there is a difference among the three processes.A summary of the findings is shown below. A manufacturer of automobile transmissions uses three different processes.Management ordered a study of the production costs to see if there is a difference among the three processes.A summary of the findings is shown below.   What is the mean square for treatments? What is the mean square for treatments?

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When H0 is rejected in ANOVA,_______ _______ are constructed to identify pairs of means that differ.

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An F statistic is:

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A random sample of 40 companies with assets over $10 million was selected and asked for their annual computer technology expense and industry.The ANOVA comparing the average computer technology expense among three industries rejected the null hypothesis.The Mean Square Error (MSE)was 195.The following table summarized the results: A random sample of 40 companies with assets over $10 million was selected and asked for their annual computer technology expense and industry.The ANOVA comparing the average computer technology expense among three industries rejected the null hypothesis.The Mean Square Error (MSE)was 195.The following table summarized the results:   Based on the comparison between the mean computer technology expense for companies in the Tax Service and Food Service industries,the 95% confidence interval shows an interval of -14.85 to 5.85 for the difference.This result indicates that Based on the comparison between the mean computer technology expense for companies in the Tax Service and Food Service industries,the 95% confidence interval shows an interval of -14.85 to 5.85 for the difference.This result indicates that

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A random sample of 30 executives from companies with assets over $1 million was selected and asked for their annual income and level of education.The ANOVA comparing the average income among three levels of education rejected the null hypothesis.The Mean Square Error (MSE)was 243.7.The following table summarized the results: A random sample of 30 executives from companies with assets over $1 million was selected and asked for their annual income and level of education.The ANOVA comparing the average income among three levels of education rejected the null hypothesis.The Mean Square Error (MSE)was 243.7.The following table summarized the results:   Based on the comparison between the mean annual incomes for executives with Undergraduate and Master's Degree or more, Based on the comparison between the mean annual incomes for executives with Undergraduate and Master's Degree or more,

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A random sample of 40 companies with assets over $10 million was selected and asked for their annual computer technology expense and industry.The ANOVA comparing the average computer technology expense among three industries rejected the null hypothesis.The Mean Square Error (MSE)was 195.The following table summarized the results: A random sample of 40 companies with assets over $10 million was selected and asked for their annual computer technology expense and industry.The ANOVA comparing the average computer technology expense among three industries rejected the null hypothesis.The Mean Square Error (MSE)was 195.The following table summarized the results:   When comparing the mean annual computer technology expense for companies in the Education and Tax services industries,the following 95% confidence interval can be constructed: When comparing the mean annual computer technology expense for companies in the Education and Tax services industries,the following 95% confidence interval can be constructed:

(Multiple Choice)
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Two accounting professors decided to compare the variance of their grading procedures.To accomplish this they each graded the same 10 exams with the following results: Two accounting professors decided to compare the variance of their grading procedures.To accomplish this they each graded the same 10 exams with the following results:   What is the critical value of F at the 0.01 level of significance? What is the critical value of F at the 0.01 level of significance?

(Multiple Choice)
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A manufacturer of automobile transmissions uses three different processes.Management ordered a study of the production costs to see if there is a difference among the three processes.A summary of the findings is shown below. A manufacturer of automobile transmissions uses three different processes.Management ordered a study of the production costs to see if there is a difference among the three processes.A summary of the findings is shown below.   What is the sum of squares of the error? What is the sum of squares of the error?

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Two accounting professors decided to compare the variance of their grading procedures.To accomplish this they each graded the same 10 exams with the following results: Two accounting professors decided to compare the variance of their grading procedures.To accomplish this they each graded the same 10 exams with the following results:   The calculated F ratio is The calculated F ratio is

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When testing for differences between treatment means,the degrees of freedom for the t statistic are:

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Assuming that the larger of two variances is in the numerator of an F statistic,in which tail of the F distribution is the rejection region for analysis of variance? ________

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If the computed value of F is 0.99 and the critical value is 3.89,we would not reject the null hypothesis.

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Given the following Analysis of Variance table for three treatments each with six observations. Given the following Analysis of Variance table for three treatments each with six observations.   What are the degrees of freedom for the treatment and error sum of squares? What are the degrees of freedom for the treatment and error sum of squares?

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In ANOVA analysis,when the null hypothesis is rejected,we can test for differences between treatment means by

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Given the following Analysis of Variance table for three treatments each with six observations. Given the following Analysis of Variance table for three treatments each with six observations.   What is the decision regarding the null hypothesis? What is the decision regarding the null hypothesis?

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