Multiple Choice
Calcium-39 undergoes positron decay. Each positron carries 5.49 MeV of energy. How much energy will be emitted when 0.00250 mol of calcium-39 decays? (1 MeV = 1.602 × 10-13 J)
A) 13.2 kJ
B) 1.32 × 104 kJ
C) 1.32 × 106 kJ
D) 1.32 × 109 kJ
E) None of these choices is correct.
Correct Answer:
Verified
Correct Answer:
Verified
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