Solved

Given That ΔH°f [Ag2S(s)] = -32

Question 97

Multiple Choice

Given that ΔH°f [Ag2S(s) ] = -32.6 kJ/mole, what is the enthalpy change for the precipitation of argentite, Ag2S(s) ? ΔH°f [Ag+(aq) ] = +105.6 kJ/mol
ΔH°f [S2-(aq) ] = +33.05 kJ/mol


A) -276.9 kJ/mol
B) -106.1 kJ/mol
C) +171.2 kJ/mol
D) +106.1 kJ/mol
E) +138.7 kJ/mol

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions