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Find the Absolute Maximum and Minimum Values Of f(x)=xx2+1+1f ( x ) = \frac { x } { x ^ { 2 } + 1 } + 1

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Find the absolute maximum and minimum values of f(x)=xx2+1+1f ( x ) = \frac { x } { x ^ { 2 } + 1 } + 1 on the interval [0,2π][ 0,2 \pi ] .

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