Given $f ( x ) = x ^ { 2 } - 3$

Given $f ( x ) = x ^ { 2 } - 3$ , use Newton's method to find the iterative formula for $x _ { n + 1 }$ .

A) $x _ { n + 1 } = x _ { n } + \frac { 1 } { 2 x _ { n } }$

B) $x _ { n + 1 } = x _ { n } + \frac { 3 } { 2 x _ { n } }$
C) $x _ { n + 1 } = \frac { x _ { n } } { 2 } - \frac { 3 } { 2 x _ { n } }$
D) $x _ { n + 1 } = x _ { n } + \frac { 3 } { x _ { n } }$
E) $x _ { n + 1 } = x _ { n } - \frac { 1 } { 2 x _ { n } }$
F) $x _ { n + 1 } = x _ { n } - \frac { 3 } { 2 x _ { n } }$


G) $x _ { n + 1 } = \frac { x _ { n } } { 2 } + \frac { 3 } { 2 x _ { n } }$

H) None of these

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