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Let f(x)=∫3x2sin⁡tt2+1dt. Find f′(x)f ( x ) = \int _ { 3 x } ^ { 2 } \frac { \sin t } { t ^ { 2 } + 1 } d t . \text { Find } f ^ { \prime } ( x )

Question 26

Short Answer

Let f(x)=∫3x2sin⁡tt2+1dt. Find f′(x)f ( x ) = \int _ { 3 x } ^ { 2 } \frac { \sin t } { t ^ { 2 } + 1 } d t . \text { Find } f ^ { \prime } ( x )
A) sin⁡3x3x2+1\frac { \sin 3 x } { 3 x ^ { 2 } + 1 }

B) −3sin⁡3x3x2+1- \frac { 3 \sin 3 x } { 3 x ^ { 2 } + 1 }
C) cos⁡xx2+1\frac { \cos x } { x ^ { 2 } + 1 }
D) −3sin⁡3x9x2+1- \frac { 3 \sin 3 x } { 9 x ^ { 2 } + 1 }
E) 3sin⁡3x9x2+1\frac { 3 \sin 3 x } { 9 x ^ { 2 } + 1 }
F) −cos⁡3x9x2+1- \frac { \cos 3 x } { 9 x ^ { 2 } + 1 }

G) cos⁡x2x\frac { \cos x } { 2 x }

H) −cos⁡x2x- \frac { \cos x } { 2 x }

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