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A Direction Field Is Given Below $\frac { d y } { d x } = \sin x$

Question 109

Multiple Choice

A direction field is given below. Which of the following represents its differential equation? $A direction field is given below. Which of the following represents its differential equation? A) \frac { d y } { d x } = \sin x B) \frac { d y } { d x } = - y C) \frac { d y } { d x } = y - \frac { 1 } { 2 } y ^ { 2 } D) \frac { d y } { d x } = x + y E) \frac { d y } { d x } = x ^ { 2 } F) \frac { d y } { d x } = 1 G) \frac { d y } { d x } = y ^ { 2 } H) \frac { d y } { d x } = x ^ { 2 } + y ^ { 2 }$

A) $\frac { d y } { d x } = \sin x$
B) $\frac { d y } { d x } = - y$
C) $\frac { d y } { d x } = y - \frac { 1 } { 2 } y ^ { 2 }$
D) $\frac { d y } { d x } = x + y$
E) $\frac { d y } { d x } = x ^ { 2 }$
F) $\frac { d y } { d x } = 1$
G) $\frac { d y } { d x } = y ^ { 2 }$
H) $\frac { d y } { d x } = x ^ { 2 } + y ^ { 2 }$

A Direction Field Is Given Below dydx=sin⁡x\frac { d y } { d x } = \sin xdxdy​=sinx

Multiple Choice

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A Direction Field Is Given Below $\frac { d y } { d x } = \sin x$

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