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Consider the Differential Equation dydt=2tx+xt2+t\frac { d y } { d t } = \frac { 2 t x + x } { t ^ { 2 } + t }

Question 117

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Consider the differential equation dydt=2tx+xt2+t\frac { d y } { d t } = \frac { 2 t x + x } { t ^ { 2 } + t } .(a) Find the general solution to the differential equation.(b) Find the solution that satisfies the initial condition x(1)=2x ( 1 ) = 2 .

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