Solve the Initial-Value Problem $t \frac { d y } { d t } = y ( y - 1 )$

Solve the initial-value problem $t \frac { d y } { d t } = y ( y - 1 )$ , $y ( 2 ) = 4$ .

A) $y = - \frac { 8 } { 8 + 3 t }$
B) $y ^ { 2 } - y = 6 t$
C) $y = - \frac { 8 } { 8 - 3 t }$
D) $y ^ { 2 } - y = 6 t$
E) $y = \frac { 8 } { 8 - 3 t }$
F) $y ^ { 2 } = 8 t$
G) $y = \frac { 1 } { 1 - t }$
H) $y ^ { 2 } + y = 6 t$

Correct Answer:

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