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Determine Whether Each of the Following Series Converges ∑n=1∞2+(−1)n2n\sum _ { n = 1 } ^ { \infty } \frac { 2 + ( - 1 ) ^ { n } } { 2 ^ { n } }

Question 229

Short Answer

Determine whether each of the following series converges. Justify your answer by specifying which test you are using and showing any necessary computation.
(a) ∑n=1∞2+(−1)n2n\sum _ { n = 1 } ^ { \infty } \frac { 2 + ( - 1 ) ^ { n } } { 2 ^ { n } }
(b) ∑n=1∞n2+13n3−n+2\sum _ { n = 1 } ^ { \infty } \frac { n ^ { 2 } + 1 } { 3 n ^ { 3 } - n + 2 }
(c) ∑n=1∞(1+sin⁡nn)2\sum _ { n = 1 } ^ { \infty } \left( \frac { 1 + \sin n } { n } \right) ^ { 2 }
(d) ∑n=1∞n!1⋅3⋅5⋯⋯(2n−1)\sum _ { n = 1 } ^ { \infty } \frac { n ! } { 1 \cdot 3 \cdot 5 \cdots \cdots ( 2 n - 1 ) }
(e) ∑n=1∞n!nn\sum _ { n = 1 } ^ { \infty } \frac { n ! } { n ^ { n } }
(f) ∑n=1∞(ln⁡nn)n\sum _ { n = 1 } ^ { \infty } \left( \frac { \ln n } { n } \right) ^ { n }
(g) ∑n=1∞1n1+ln⁡n\sum _ { n = 1 } ^ { \infty } \frac { 1 } { n \sqrt { 1 + \ln n } }
(h) ∑n=1∞ln⁡n(n+1)3\sum _ { n = 1 } ^ { \infty } \frac { \ln n } { ( n + 1 ) ^ { 3 } }
(i) ∑n=1∞3nsin⁡(π4n)\sum _ { n = 1 } ^ { \infty } 3 ^ { n } \sin \left( \frac { \pi } { 4 ^ { n } } \right)
(j) ∑n=1∞tan⁡−1n\sum _ { n = 1 } ^ { \infty } \tan ^ { - 1 } n
(k) ∑n=1∞(−1)nln⁡nn\sum _ { n = 1 } ^ { \infty } ( - 1 ) ^ { n } \frac { \ln n } { n }
(l) ∑n=1∞ln⁡(1+1n)\sum _ { n = 1 } ^ { \infty } \ln \left( 1 + \frac { 1 } { n } \right)
(m) ∑n=1∞2nn!2⋅5⋅8⋅…(3n−1)\sum _ { n = 1 } ^ { \infty } \frac { 2 ^ { n } n ! } { 2 \cdot 5 \cdot 8 \cdot \ldots ( 3 n - 1 ) }
(n) ∑n=1∞n+1−nn\sum _ { n = 1 } ^ { \infty } \frac { \sqrt { n + 1 } - \sqrt { n } } { n }

Correct Answer:

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(a) Converges
(b) Diverges
(c)...

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