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Examine the Two Series Below for Absolute Convergence (A), Convergence $\sum _ { n = 1 } ^ { \infty } \frac { ( - 1 ) ^ { n - 1 } } { \ln ( n + 1 ) }$

Question 55

Multiple Choice

Examine the two series below for absolute convergence (A) , convergence that is not absolute (C) , or divergence (D) .
1) $\sum _ { n = 1 } ^ { \infty } \frac { ( - 1 ) ^ { n - 1 } } { \ln ( n + 1 ) }$
2) $\sum _ { n = 1 } ^ { \infty } \frac { ( - 1 ) ^ { n - 1 } } { ( \ln ( n + 1 ) ) ^ { 2 } }$

A) 1A, 2A
B) 1A, 2C
C) 1A, 2D
D) 1C, 2A
E) 1C, 2C
F) 1C, 2D
G) 1D, 2A
H) 1D, 2C

Examine the Two Series Below for Absolute Convergence (A), Convergence ∑n=1∞(−1)n−1ln⁡(n+1)\sum _ { n = 1 } ^ { \infty } \frac { ( - 1 ) ^ { n - 1 } } { \ln ( n + 1 ) }∑n=1∞​ln(n+1)(−1)n−1​

Multiple Choice

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Examine the Two Series Below for Absolute Convergence (A), Convergence $\sum _ { n = 1 } ^ { \infty } \frac { ( - 1 ) ^ { n - 1 } } { \ln ( n + 1 ) }$

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