Essay
The text describes logistic growth with an equation for the actual population in terms of a growth constant and a maximum population (carrying capacity), 
. The equation could also be written for a fraction of the maximum population in terms of a fractional growth constant. Re-express the differential equation in terms of the fractional population, 
. Compare the time it takes for the population to go from 60% of the maximum to 80% of the maximum with the time it takes to go from 80% of the maximum to 90% of the maximum,
if k = 0.00020 day-1 and M = 5000?
Correct Answer:
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time(60-80%) = 0.98...View Answer
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Correct Answer:
Verified
time(60-80%) = 0.98...View Answer
Unlock this answer now
Get Access to more Verified Answers free of charge
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