The Angular Acceleration of the Flywheel of a Generator Is $\alpha$

The angular acceleration of the flywheel of a generator is given by
$\alpha$ (t) = 6bt - 12ct²
Where b and c are constants and $\alpha$ is in rad/s² provided t is in seconds. If the initial angular velocity is taken to be $\omega$ ₀, the angular velocity at time t is given by

A) $\omega$ ₀ + 6bt² - 12ct³
B) 6b - 24ct
C) 3bt² - 4ct³ + $\omega$ ₀
D) 3bt² - 4ct³
E) 6b - 24ct + $\omega$ ₀

Correct Answer:

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