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Two Masses M1 and M2 (With M2 > M1) Are ×\times

Question 97

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Two masses m1 and m2 (with m2 > m1) are connected by a massless rope hung over a frictionless light pulley. If the masses are released then the acceleration of m2 in the downward direction is given by  Two masses m<sub>1</sub> and m<sub>2</sub> (with m<sub>2</sub> > m<sub>1</sub>)  are connected by a massless rope hung over a frictionless light pulley. If the masses are released then the acceleration of m<sub>2</sub> in the downward direction is given by   A)  (m<sub>2</sub> - m<sub>1</sub>)   \times  g/(m<sub>1</sub> - m<sub>2</sub>)  B)  (m<sub>2</sub> - m<sub>1</sub>)   \times  g/(m<sub>1</sub> + m<sub>2</sub>)  C)  (m<sub>1</sub> + m<sub>2</sub>)   \times  g/(m<sub>2</sub> - m<sub>1</sub>)  D)  m<sub>2</sub>  \times  g/(m<sub>1</sub> + m<sub>2</sub>)  E)  g


A) (m2 - m1) ×\times g/(m1 - m2)
B) (m2 - m1) ×\times g/(m1 + m2)
C) (m1 + m2) ×\times g/(m2 - m1)
D) m2 ×\times g/(m1 + m2)
E) g

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