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Solve the System of Equations {x+3y−2z=12x+4y+z=−42x+6y−z=2\left\{ \begin{array} { r } x + 3 y - 2 z = 1 \\2 x + 4 y + z = - 4 \\2 x + 6 y - z = 2\end{array} \right.

Question 121

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Solve the system of equations {x+3y−2z=12x+4y+z=−42x+6y−z=2\left\{ \begin{array} { r } x + 3 y - 2 z = 1 \\2 x + 4 y + z = - 4 \\2 x + 6 y - z = 2\end{array} \right. by converting to a matrix equation and using its inverse coefficient matrix [5332−116−23−1256−23013]\left[ \begin{array} { c c c } \frac { 5 } { 3 } & \frac { 3 } { 2 } & - \frac { 11 } { 6 } \\\\- \frac { 2 } { 3 } & - \frac { 1 } { 2 } & \frac { 5 } { 6 } \\\\- \frac { 2 } { 3 } & 0 & \frac { 1 } { 3 }\end{array} \right] .

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