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Use Back-Substitution to Solve the Triangular System {x−3y−z=02y−8z=214z=−1\left\{ \begin{aligned}x - 3 y - z & = 0 \\2 y - 8 z & = 2 \\\frac { 1 } { 4 } z & = - 1\end{aligned} \right.

Question 79

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Use back-substitution to solve the triangular system. {x−3y−z=02y−8z=214z=−1\left\{ \begin{aligned}x - 3 y - z & = 0 \\2 y - 8 z & = 2 \\\frac { 1 } { 4 } z & = - 1\end{aligned} \right.

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