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Use the Formula tan⁡ψ=∣m2−m11+m1m2∣\tan \psi = \left| \frac { m _ { 2 } - m _ { 1 } } { 1 + m _ { 1 } m _ { 2 } } \right|

Question 28

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Use the formula tan⁡ψ=∣m2−m11+m1m2∣\tan \psi = \left| \frac { m _ { 2 } - m _ { 1 } } { 1 + m _ { 1 } m _ { 2 } } \right| to find the acute angle ψ\psi formed by the two lines y−x=0y - x = 0 and 2x−3y=12 x - 3 y = 1 .

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