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Let a and B Be Real Numbers $\int_{-\infty}^{a} \frac{10}{x^{2}+9} d x+\int_{a}^{\infty} \frac{10}{x^{2}+9} d x=?+\int_{b}^{\infty} \frac{10}{x^{2}+9} d x$

Question 91

Multiple Choice

Let a and b be real numbers. What integral must appear in place of the question mark "?" to make the following statement true? $\int_{-\infty}^{a} \frac{10}{x^{2}+9} d x+\int_{a}^{\infty} \frac{10}{x^{2}+9} d x=?+\int_{b}^{\infty} \frac{10}{x^{2}+9} d x$

A) $\int_{-\infty}^{a} \frac{9}{x^{2}+10} d x$
B) $\int_{0}^{-\infty} \frac{10}{x^{2}-9} d x$
C) $\int_{-\infty}^{b} \frac{10}{x^{2}+9} d x$
D) $\int_{0}^{-\infty} \frac{10}{x^{2}+9} d x$
E) $\text { none of these }$

Let a and B Be Real Numbers ∫−∞a10x2+9dx+∫a∞10x2+9dx=?+∫b∞10x2+9dx\int_{-\infty}^{a} \frac{10}{x^{2}+9} d x+\int_{a}^{\infty} \frac{10}{x^{2}+9} d x=?+\int_{b}^{\infty} \frac{10}{x^{2}+9} d x∫−∞a​x2+910​dx+∫a∞​x2+910​dx=?+∫b∞​x2+910​dx

Multiple Choice

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Let a and B Be Real Numbers $\int_{-\infty}^{a} \frac{10}{x^{2}+9} d x+\int_{a}^{\infty} \frac{10}{x^{2}+9} d x=?+\int_{b}^{\infty} \frac{10}{x^{2}+9} d x$

Correct Answer:
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