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Find the Acceleration of a Particle with the Given Position r(t)=9sin⁡ti+10tj−8cos⁡tk\mathbf { r } ( t ) = 9 \sin t \mathbf { i } + 10 t \mathbf { j } - 8 \cos t \mathbf { k }

Question 49

Multiple Choice

Find the acceleration of a particle with the given position function. r(t) =9sin⁡ti+10tj−8cos⁡tk\mathbf { r } ( t ) = 9 \sin t \mathbf { i } + 10 t \mathbf { j } - 8 \cos t \mathbf { k }


A) a(t) =−9sin⁡ti−9cos⁡tj\mathbf { a } ( t ) = - 9 \sin t \mathbf { i } - 9 \cos t \mathbf { j }
B) a(t) =−9sin⁡ti+9cos⁡tj\mathbf { a } ( t ) = - 9 \sin t \mathbf { i } + 9 \cos t \mathbf { j }
C) a(t) =−9sin⁡ti+10cos⁡tk\mathbf { a } ( t ) = - 9 \sin t \mathbf { i } + 10 \cos t \mathbf { k }
D) a(t) =−9sin⁡ti+8cos⁡tk\mathbf { a } ( t ) = - 9 \sin t \mathbf { i } + 8 \cos t \mathbf { k }
E) a(t) =9sin⁡ti−10tk\mathbf { a } ( t ) = 9 \sin t \mathbf { i } - 10 t \mathbf { k }

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