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In the Previous Problem, the Amount of Chemical C,X(t)C , X ( t )

Question 15

Multiple Choice

In the previous problem, the amount of chemical C,X(t) C , X ( t ) , produced by time t is


A) x=2000(1−e−25kt/3) /(16−15e−25kt/3) , where k=3ln⁡(5/4) /250x = 2000 \left( 1 - e ^ { - 25 k t / 3 } \right) / \left( 16 - 15 e ^ { - 25 k t / 3 } \right) , \text { where } k = 3 \ln ( 5 / 4 ) / 250
B) x=2000(1−e−125kt) /(4−e−125kt) , where k=ln⁡(19/16) /1250x = 2000 \left( 1 - e ^ { - 125 k t } \right) / \left( 4 - e ^ { - 125 k t } \right) , \text { where } k = \ln ( 19 / 16 ) / 1250
C) x=400(1−e−25kt/3) /(3−e−25kt/3) , where k=3ln⁡(3) /250x = 400 \left( 1 - e ^ { - 25 k t / 3 } \right) / \left( 3 - e ^ { - 25 k t / 3 } \right) , \text { where } k = 3 \ln ( 3 ) / 250
D) x=400(1−e−125kt) /(3−e−125kt) , where k=ln⁡(3) /1250x = 400 \left( 1 - e ^ { - 125 k t } \right) / \left( 3 - e ^ { - 125 k t } \right) , \text { where } k = \ln ( 3 ) / 1250
E) x=800(1−e−25kt/3) /(4−e−25kt/3) , where k=3ln⁡(7/4) /250x = 800 \left( 1 - e ^ { - 25 k t / 3 } \right) / \left( 4 - e ^ { - 25 k t / 3 } \right) , \text { where } k = 3 \ln ( 7 / 4 ) / 250

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