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Two Linearly Independent Solutions of the Differential Equation y′′−4y′+5y=0y ^ { \prime \prime } - 4 y ^ { \prime } + 5 y = 0

Question 35

Multiple Choice

Two linearly independent solutions of the differential equation y′′−4y′+5y=0y ^ { \prime \prime } - 4 y ^ { \prime } + 5 y = 0 are


A) y1=ex,y2=e5xy _ { 1 } = e ^ { x } , y _ { 2 } = e ^ { 5 x }
B) y1=e−x,y2=e−5xy _ { 1 } = e ^ { - x } , y _ { 2 } = e ^ { - 5 x }
C) y1=e2xcos⁡x,y2=e2xsin⁡xy _ { 1 } = e ^ { 2 x } \cos x , y _ { 2 } = e ^ { 2 x } \sin x
D) y1=excos⁡(2x) ,y2=exsin⁡(2x) y _ { 1 } = e ^ { x } \cos ( 2 x ) , y _ { 2 } = e ^ { x } \sin ( 2 x )
E) y1=e−xcos⁡(2x) ,y2=e−2xsin⁡(2x) y _ { 1 } = e ^ { - x } \cos ( 2 x ) , y _ { 2 } = e ^ { - 2 x } \sin ( 2 x )

Correct Answer:

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