For the Equation $\left( x ^ { 2 } - 16 \right) ^ { 3 } ( x - 1 ) y ^ { \prime \prime } - 2 x y ^ { \prime } + y = 0$

For the equation $\left( x ^ { 2 } - 16 \right) ^ { 3 } ( x - 1 ) y ^ { \prime \prime } - 2 x y ^ { \prime } + y = 0$ , the point $x = 4$ is

A) an ordinary point
B) a regular singular point
C) an irregular singular point
D) a special point
E) none of the above

Correct Answer:

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