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The Solution of the System X′=(2−222)X\mathbf { X } ^ { \prime } = \left( \begin{array} { c c } 2 & - 2 \\2 & 2\end{array} \right) \mathbf { X }

Question 35

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The solution of the system X′=(2−222) X\mathbf { X } ^ { \prime } = \left( \begin{array} { c c } 2 & - 2 \\2 & 2\end{array} \right) \mathbf { X } is


A) X=c1e2t[(01) cos⁡(2t) −(01) sin⁡(2t) ]+c2e2t[(10) cos⁡(2t) +(01) sin⁡(2t) ]\mathbf { X } = c _ { 1 } e ^ { 2 t } \left[ \left( \begin{array} { l } 0 \\1\end{array} \right) \cos ( 2 t ) - \left( \begin{array} { l } 0 \\1\end{array} \right) \sin ( 2 t ) \right] + c _ { 2 } e ^ { 2 t } \left[ \left( \begin{array} { l } 1 \\0\end{array} \right) \cos ( 2 t ) + \left( \begin{array} { l } 0 \\1\end{array} \right) \sin ( 2 t ) \right]
B) X=c1e−2t[(01) cos⁡(2t) −(10) sin⁡(2t) ]+c2e−2t[(10) cos⁡(2t) +(01) sin⁡(2t) ]\mathbf { X } = c _ { 1 } e ^ { - 2 t } \left[ \left( \begin{array} { l } 0 \\1\end{array} \right) \cos ( 2 t ) - \left( \begin{array} { l } 1 \\0\end{array} \right) \sin ( 2 t ) \right] + c _ { 2 } e ^ { - 2 t } \left[ \left( \begin{array} { l } 1 \\0\end{array} \right) \cos ( 2 t ) + \left( \begin{array} { l } 0 \\1\end{array} \right) \sin ( 2 t ) \right]
C) X=c1e2t[(01) cos⁡t+(10) sin⁡t]+c2e2t[(10) cos⁡t+(01) sin⁡t]\mathrm { X } = c _ { 1 } e ^ { 2 t } \left[ \left( \begin{array} { l } 0 \\1\end{array} \right) \cos t + \left( \begin{array} { l } 1 \\0\end{array} \right) \sin t \right] + c _ { 2 } e ^ { 2 t } \left[ \left( \begin{array} { l } 1 \\0\end{array} \right) \cos t + \left( \begin{array} { l } 0 \\1\end{array} \right) \sin t \right]
D) X=c1e−2t[(01) cos⁡t−(10) sin⁡t]+c2e−2t[(10) cos⁡t+(01) sin⁡t]\mathrm { X } = c _ { 1 } e ^ { - 2 t } \left[ \left( \begin{array} { l } 0 \\1\end{array} \right) \cos t - \left( \begin{array} { l } 1 \\0\end{array} \right) \sin t \right] + c _ { 2 } e ^ { - 2 t } \left[ \left( \begin{array} { l } 1 \\0\end{array} \right) \cos t + \left( \begin{array} { l } 0 \\1\end{array} \right) \sin t \right]
E) none of the above

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