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The Solution of the Eigenvalue Problem y′′+λy=0,y(0)=0,y′(1)=0y ^ { \prime \prime } + \lambda y = 0 , y ( 0 ) = 0 , y ^ { \prime } ( 1 ) = 0

Question 7

Multiple Choice

The solution of the eigenvalue problem y′′+λy=0,y(0) =0,y′(1) =0y ^ { \prime \prime } + \lambda y = 0 , y ( 0 ) = 0 , y ^ { \prime } ( 1 ) = 0 is


A) λ=(n−1/2) π,y=cos⁡((n−1/2) πx) +sin⁡((n−1/2) πx) ,n=1,2,3,…\lambda = ( n - 1 / 2 ) \pi , y = \cos ( ( n - 1 / 2 ) \pi x ) + \sin ( ( n - 1 / 2 ) \pi x ) , n = 1,2,3 , \ldots
B) λ=(n−1/2) π,y=cos⁡((n−1/2) πx) ,n=1,2,3,…\lambda = ( n - 1 / 2 ) \pi , y = \cos ( ( n - 1 / 2 ) \pi x ) , n = 1,2,3 , \ldots
C) λ=(n−1/2) π,y=sin⁡((n−1/2) πx) ,n=1,2,3,…\lambda = ( n - 1 / 2 ) \pi , y = \sin ( ( n - 1 / 2 ) \pi x ) , n = 1,2,3 , \ldots
D) λ=(n−1/2) 2π2,y=cos⁡((n−1/2) πx) ,n=1,2,3,…\lambda = ( n - 1 / 2 ) ^ { 2 } \pi ^ { 2 } , y = \cos ( ( n - 1 / 2 ) \pi x ) , n = 1,2,3 , \ldots
E) λ=(n−1/2) 2π2,y=sin⁡((n−1/2) πx) ,n=1,2,3,…\lambda = ( n - 1 / 2 ) ^ { 2 } \pi ^ { 2 } , y = \sin ( ( n - 1 / 2 ) \pi x ) , n = 1,2,3 , \ldots

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