In the Previous Two Problems, the Product Solutions Are
A) $\sin ( n \pi x / L ) e ^ { n x / L }$

In the previous two problems, the product solutions are

A) $\sin ( n \pi x / L ) e ^ { n x / L }$
B) $\sin ( n \pi x / L ) e ^ { - n x / L }$
C) $\cos ( n \pi x / L ) e ^ { ( n \pi / D ) ^ { 2 } t }$
D) $\sin ( n \pi x / L ) e ^ { - ( n \pi / L ) ^ { 2 } t }$
E) $\cos ( n \pi x / L ) e ^ { - n t / L }$

Correct Answer:

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