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In the Previous Problem, Apply the Laplace Transform U(x,s)=L{u(x,t)}U ( x , s ) = \mathcal { L } \{ u ( x , t ) \}

Question 29

Multiple Choice

In the previous problem, apply the Laplace transform. The resulting equation for U(x,s) =L{u(x,t) }U ( x , s ) = \mathcal { L } \{ u ( x , t ) \} is


A) a2∂2U∂x2+s2U=−sf(x) a ^ { 2 } \frac { \partial ^ { 2 } U } { \partial x ^ { 2 } } + s ^ { 2 } U = - s f ( x )
B) a2∂2U∂x2+s2U=0a ^ { 2 } \frac { \partial ^ { 2 } U } { \partial x ^ { 2 } } + s ^ { 2 } U = 0
C) a2∂2U∂x2−s2U=−f(x) a ^ { 2 } \frac { \partial ^ { 2 } U } { \partial x ^ { 2 } } - s ^ { 2 } U = - f ( x )
D) a2∂2U∂x2−s2U=sf(x) a ^ { 2 } \frac { \partial ^ { 2 } U } { \partial x ^ { 2 } } - s ^ { 2 } U = s f ( x )
E) a2∂2U∂x2−s2U=0a ^ { 2 } \frac { \partial ^ { 2 } U } { \partial x ^ { 2 } } - s ^ { 2 } U = 0

Correct Answer:

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