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The Solution Of X′=(1−21−1)X\mathbf { X } ^ { \prime } = \left( \begin{array} { l l } 1 & - 2 \\1 & - 1\end{array} \right) \mathbf { X }

Question 25

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The solution of X′=(1−21−1) X\mathbf { X } ^ { \prime } = \left( \begin{array} { l l } 1 & - 2 \\1 & - 1\end{array} \right) \mathbf { X } is


A) X=c1[(21) cos⁡t−(0−1) sin⁡t]+c2[(21) sin⁡t+(0−1) cos⁡t]\mathbf { X } = c _ { 1 } \left[ \left( \begin{array} { l } 2 \\1\end{array} \right) \cos t - \left( \begin{array} { c } 0 \\- 1\end{array} \right) \sin t \right] + c _ { 2 } \left[ \left( \begin{array} { l } 2 \\1\end{array} \right) \sin t + \left( \begin{array} { c } 0 \\- 1\end{array} \right) \cos t \right]
B) X=c1(10) e3t+c2(01) e−3tX = c _ { 1 } \left( \begin{array} { l } 1 \\0\end{array} \right) e ^ { \sqrt { 3 } t } + c _ { 2 } \left( \begin{array} { l } 0 \\1\end{array} \right) e ^ { - \sqrt { 3 } t }
C) X=c1(10) et+c2(01) e−t\mathbf { X } = c _ { 1 } \left( \begin{array} { l } 1 \\0\end{array} \right) e ^ { t } + c _ { 2 } \left( \begin{array} { l } 0 \\1\end{array} \right) e ^ { - t }
D) X=c1[(21) cos⁡(3t) −(0−1) sin⁡(3t) ]+c2[(21) sin⁡(3t) +(0−1) cos⁡(3t) ]\begin{array} { l } \mathrm { X } = c _ { 1 } \left[ \left( \begin{array} { l } 2 \\1\end{array} \right) \cos ( \sqrt { 3 } t ) - \left( \begin{array} { c } 0 \\- 1\end{array} \right) \sin ( \sqrt { 3 } t ) \right] + \\c _ { 2 } \left[ \left( \begin{array} { l } 2 \\1\end{array} \right) \sin ( \sqrt { 3 } t ) + \left( \begin{array} { c } 0 \\- 1\end{array} \right) \cos ( \sqrt { 3 } t ) \right]\end{array}
E) X=c1[(21) cos⁡(2t) −(0−1) sin⁡(2t) ]+c2[(21) sin⁡(2t) +(0−1) cos⁡(2t) ]\mathbf { X } = c _ { 1 } \left[ \left( \begin{array} { l } 2 \\1\end{array} \right) \cos ( 2 t ) - \left( \begin{array} { c } 0 \\- 1\end{array} \right) \sin ( 2 t ) \right] + c _ { 2 } \left[ \left( \begin{array} { l } 2 \\1\end{array} \right) \sin ( 2 t ) + \left( \begin{array} { c } 0 \\- 1\end{array} \right) \cos ( 2 t ) \right]

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