The Solution Of $y ^ { \prime \prime } - 4 y ^ { \prime } + 20 y = 0$

The solution of $y ^ { \prime \prime } - 4 y ^ { \prime } + 20 y = 0$ is

A) $y = c _ { 1 } e ^ { - 2 x } \cos ( 4 x ) + c _ { 2 } e ^ { - 2 x } \sin ( 4 x )$
B) $y = c _ { 1 } e ^ { - 2 x } \cos ( 4 x ) + c _ { 2 } e ^ { 2 x } \sin ( 4 x )$
C) $y = c _ { 1 } e ^ { 2 x } \cos ( 4 x ) + c _ { 2 } e ^ { 2 x } \sin ( 4 x )$
D) $y = c _ { 1 } e ^ { 2 x } + c _ { 2 } e ^ { 4 x }$
E) $y = c _ { 1 } \cos ( 4 x ) + c _ { 2 } \sin ( 4 x )$

Correct Answer:

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