Use the Quadratic Formula to Solve For $y$ ​ $x ^ { 2 } + 12 x y + 36 y ^ { 2 } - 5 x - y - 3 = 0$

Use the Quadratic Formula to solve for $y$ .​ $x ^ { 2 } + 12 x y + 36 y ^ { 2 } - 5 x - y - 3 = 0$ ​

A) $y = \frac { - ( 36 x + 1 ) \pm \sqrt { ( 36 x - 1 ) ^ { 2 } - 144 \left( x ^ { 2 } - 5 x - 3 \right) } } { 72 }$
B) $y = \frac { - ( 12 x + 1 ) \pm \sqrt { ( 36 x + 1 ) ^ { 2 } - 144 \left( x ^ { 2 } + 5 x + 3 \right) } } { 72 }$
C) $y = \frac { - ( 36 x - 1 ) \pm \sqrt { ( 36 x - 1 ) ^ { 2 } - 144 \left( x ^ { 2 } - 5 x + 3 \right) } } { 72 }$
D) $y = \frac { ( 36 x - 1 ) \pm \sqrt { ( 36 x - 1 ) ^ { 2 } - 144 \left( x ^ { 2 } - 5 x - 3 \right) } } { 72 }$
E) $y = \frac { - ( 12 x - 1 ) \pm \sqrt { ( 12 x - 1 ) ^ { 2 } - 144 \left( x ^ { 2 } - 5 x - 3 \right) } } { 72 }$

Correct Answer:

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