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Complete the Table h(t)=12∣t+3∣h ( t ) = \frac { 1 } { 2 } | t + 3 |

Question 6

Multiple Choice

Complete the table. h(t) =12∣t+3∣h ( t ) = \frac { 1 } { 2 } | t + 3 |
t−11−90−5−1h(t) \begin{array} { | l | l | l | l | l | l | } \hline t & - 11 & - 9 & 0 & - 5 & - 1 \\\hline h ( t ) & & & & & \\\hline\end{array}


A)
t−11−90−5−1h(t) 34−311\begin{array} { | l | l | l | l | l | l | } \hline t & - 11 & - 9 & 0 & - 5 & - 1 \\\hline h ( t ) & 3 & 4 & - 3 & 1 & 1 \\\hline\end{array}
B) t−11−90−5−1h(t) 433211\begin{array} { | l | l | l | l | l | l | } \hline t & - 11 & - 9 & 0 & - 5 & - 1 \\\hline \\ h ( t ) & 4 & 3 & \frac{3}{2}& 1 & 1 \\\\\hline\end{array} .
C) t−11−90−5−1h(t) 431321\begin{array} { | l | l | l | l | l | l | } \hline t & - 11 & - 9 & 0 & - 5 & - 1 \\\hline \\ h ( t ) & 4 & 3 & 1 & \frac{3}{2}& 1 \\\\\hline\end{array}
D) t−11−90−5−1h(t) 433211\begin{array} { | l | l | l | l | l | l | } \hline t & - 11 & - 9 & 0 & - 5 & - 1 \\\hline \\ h ( t ) & 4 & 3 & \frac{3}{2}& 1 & 1 \\\\\hline\end{array}
E) t−11−90−5−1h(t) 43011\begin{array} { | l | l | l | l | l | l | } \hline t & - 11 & - 9 & 0 & - 5 & - 1 \\\hline h ( t ) & 4 & 3 & 0 & 1 & 1 \\\hline\end{array}

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