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Given f(x)=x2−36x+6,g(x)=x−6f ( x ) = \frac { x ^ { 2 } - 36 } { x + 6 } , g ( x ) = x - 6

Question 16

Multiple Choice

Given f(x) =x2−36x+6,g(x) =x−6f ( x ) = \frac { x ^ { 2 } - 36 } { x + 6 } , g ( x ) = x - 6 .Complete the table and explain how the two functions differ. x−8−7.5−7−6.5−6−5.5−5f(x) g(x) \begin{array} { | c | c | c | c | c | c | c | c | } \hline x & - 8 & - 7.5 & - 7 & - 6.5 & - 6 & - 5.5 & - 5 \\\hline f ( x ) & & & & & & & \\\hline g ( x ) & & & & & & & \\\hline\end{array}


A) ​ x−8−7.5−7−6.5−6−5.5−5f(x) −14−13.5 Undefined −12.5−12−11.5−11g(x) −14−13.5−13−12.5−12−11.5−11\begin{array} { | c | c | c | c | c | c | c | c | } \hline x & - 8 & - 7.5 & - 7 & - 6.5 & - 6 & - 5.5 & - 5 \\\hline f ( x ) & - 14 & - 13.5 & \text { Undefined } & - 12.5 & - 12 & - 11.5 & - 11 \\\hline g ( x ) & - 14 & - 13.5 & - 13 & - 12.5 & - 12 & - 11.5 & - 11 \\\hline\end{array}
The graph of f(x) = g(x) except when x = -7.Because the factor x + 6 canceled,there is a hole in the graph of f(x) when x = -7.​
B) ​ x−8−7.5−7−6.5−6−5.5−5f(x) −14 Undefined −13−12.5−12−11.5−11g(x) −14−13.5−13−12.5−12−11.5−11\begin{array} { | c | c | c | c | c | c | c | c | } \hline x & - 8 & - 7.5 & - 7 & - 6.5 & - 6 & - 5.5 & - 5 \\\hline f ( x ) & - 14 & \text { Undefined } & - 13 & - 12.5 & - 12 & - 11.5 & - 11 \\\hline g ( x ) & - 14 & - 13.5 & - 13 & - 12.5 & - 12 & - 11.5 & - 11 \\\hline\end{array}
​The graph of f(x) = g(x) except when x = -7.5.Because the factor x + 6 canceled,there is a hole in the graph of f(x) when x = -7.5.​
C) ​ x−8−7.5−7−6.5−6−5.5−5f(x) −14−13.5−13 Undefined −12−11.5−11g(x) −14−13.5−13−12.5−12−11.5−11\begin{array} { | c | c | c | c | c | c | c | c | } \hline x & - 8 & - 7.5 & - 7 & - 6.5 & - 6 & - 5.5 & - 5 \\\hline f ( x ) & - 14 & - 13.5 & - 13 & \text { Undefined } & - 12 & - 11.5 & - 11 \\\hline g ( x ) & - 14 & - 13.5 & - 13 & - 12.5 & - 12 & - 11.5 & - 11 \\\hline\end{array}
The graph of f(x) = g(x) except when x = -6.5.Because the factor x + 6 canceled,there is a hole in the graph of f(x) when x = -6.5.
D) ​ x−8−7.5−7−6.5−6−5.5−5f(x) −14−13.5−13−12.5 Undefined −11.5−11g(x) −14−13.5−13−12.5−12−11.5−11\begin{array} { | c | c | c | c | c | c | c | c | } \hline x & - 8 & - 7.5 & - 7 & - 6.5 & - 6 & - 5.5 & - 5 \\\hline f ( x ) & - 14 & - 13.5 & - 13 & - 12.5 & \text { Undefined } & - 11.5 & - 11 \\\hline g ( x ) & - 14 & - 13.5 & - 13 & - 12.5 & - 12 & - 11.5 & - 11 \\\hline\end{array}
The graph of f(x) = g(x) except when x = -6.Because the factor x + 6 canceled,there is a hole in the graph of f(x) when x = -6.​
E) ​ x−8−7.5−7−6.5−6−5.5−5f(x) −14−13.5−13−12.5−12 Undefined −11g(x) −14−13.5−13−12.5−12−11.5−11\begin{array} { | c | c | c | c | c | c | c | c | } \hline x & - 8 & - 7.5 & - 7 & - 6.5 & - 6 & - 5.5 & - 5 \\\hline f ( x ) & - 14 & - 13.5 & - 13 & - 12.5 & - 12 & \text { Undefined } & - 11 \\\hline g ( x ) & - 14 & - 13.5 & - 13 & - 12.5 & - 12 & - 11.5 & - 11 \\\hline\end{array}
​The graph of f(x) = g(x) except when x = -5.5.Because the factor x + 6 canceled,there is a hole in the graph f(x) when x = -5.5.​

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