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Use a Graphing Utility to Construct a Table of Values f(x)=e5xf ( x ) = e ^ { 5 x }

Question 7

Multiple Choice

Use a graphing utility to construct a table of values for the function.Round your answer to three decimal places.​ f(x) =e5xf ( x ) = e ^ { 5 x } ​


A) x−2−1012f(x) 0.0000.007−1.000148.41322,026.466\begin{array} { | l | l | l | l | l | l | } \hline x & - 2 & - 1 & 0 & 1 & 2 \\\hline f ( x ) & 0.000 & 0.007 & - 1.000 & 148.413 & 22,026.466 \\\hline\end{array}
B) x−2−1012f(x) 0.0000.0071.000−148.41322,026.466\begin{array} { | l | l | l | l | l | l | } \hline x & - 2 & - 1 & 0 & 1 & 2 \\\hline f ( x ) & 0.000 & 0.007 & 1.000 & - 148.413 & 22,026.466 \\\hline\end{array}
C) x−2−1012f(x) 0.0000.0071.000148.41322,026.466\begin{array} { | l | l | l | l | l | l | } \hline x & - 2 & - 1 & 0 & 1 & 2 \\\hline f ( x ) & 0.000 & 0.007 & 1.000 & 148.413 & 22,026.466 \\\hline\end{array}
D) x−2−1012f(x) 0.000−0.0071.000148.41322,026.466\begin{array} { | l | l | l | l | l | l | } \hline x & - 2 & - 1 & 0 & 1 & 2 \\\hline f ( x ) & 0.000 & - 0.007 & 1.000 & 148.413 & 22,026.466 \\\hline\end{array}
E) x−2−1012f(x) 0.000−0.007−1.000−148.413−22,026.466\begin{array} { | l | l | l | l | l | l | } \hline x & - 2 & - 1 & 0 & 1 & 2 \\\hline f ( x ) & 0.000 & - 0.007 & - 1.000 & - 148.413 & - 22,026.466 \\\hline\end{array}

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